Phenotypically wild-type F1 female Drosophila, whose mothers had light eyes (lt) and fathers had straw (stw) bristles, produced the following offspring when crossed to homozygous light eyed, straw bristled males: Phenotype Number light-straw 140 wild-type 160 light 360 straw 340 Total 1000 Compute the map distance between the light and straw loci. Group of answer choices 70 map units 3 map units 7 map units 0.03 map units 30 map units

Phenotypically wild-type F1 female Drosophila, whose mothers had light eyes (lt) and fathers had straw (stw) bristles, produced the following offspring when crossed to homozygous light eyed, straw bristled males: Phenotype Number light-straw 140 wild-type 160 light 360 straw 340 Total 1000 Compute the map distance between the light and straw loci. Group of answer choices 70 map units 3 map units 7 map units 0.03 map units 30 map units

Biology: The Dynamic Science (MindTap Course List)

4th Edition

ISBN:9781305389892

Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan

Chapter13: Genes, Chromosomes, And Human Genetics

Section: Chapter Questions

Problem 8TYK: Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene...

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Female Drosophila heterozygous for three recessive mutations e (ebony body), st (scarlet eyes), and ss (spineless bristles) were testcrossed, and the following progeny were obtained: Phenotype Number wild-type 67 ebony 8 ebony, scarlet 68 ebony, spineless 347 ebony, scarlet, spineless 78 scarlet 368 scarlet, spineless 10 spineless 54 (a) What indicates that the genes are linked? (b) What was the genotype of the original heterozygous females? (c) What is the order of the genes? (d) What is the map distance between e and st? (e) Between e and ss? (f) What is the coefficient of coincidence? (g) Diagram the crosses in this experiment.
In Drosophila fruit flies, the genes for warped wings (dwp), rumpled bristles (rmp), and pallid wings (pld) are linked. A trihybrid female for all three allleles is crossed with homozygous recessive male for all three alleles and the offspring obtained showed the following phenotypes: 3 pld rmp dwp 428 pld rmp + 427 + + dwp 48 + rmp + 47 pld + dwp 23 pld + + 2 + + + 22 + rmp dwp What is the order and map distance between these three alleles?
The genes for the recessive traits of mahogany eyes and ebony body are approximately 30 map units apart on chromosome III in Drosophila. Assume that a mahogany-eyed female was mated to an ebony-bodied male and that the resulting F1 females (all phenotypically wild-type) were then mated to mahogany, ebony males. Of 1000 offspring, what would be the expected phenotypes, and in what numbers would they be expected? Group of answer choices None of these is correct wild-type = 200; mahogany and ebony = 200; mahogany = 300; ebony = 300 mahogany = 200; ebony = 200; wild-type = 300; mahogany and ebony = 300 wild-type = 350; mahogany and ebony = 350; mahogany = 150; ebony = 150 mahogany = 350; ebony = 350; wild-type = 150; mahogany and ebony = 150
In Drosophila, the dominant Bar mutation (B, chromosome X, position 57) results in thin bar- shaped eyes, while the recessive singed (sn, chromosome X, position 21) results burnt looking bristles. True breeding, wild type females are mated with true breeding males with Bar eyes and singed bristles. Using Drosophila notation, diagram the P1 and F1 crosses. P1 F1 Fill in the chart with phenotypic ratios that would be expected in the F2 generation. Use the space provided to show your work. Phenotype Females Males Overall (♀and ♂) =1 =1 =1
In Drosophila flies, the allele b gives a black body, and the allele b+ gives brown, the wild-typephenotype. The allele wx of a separate gene gives waxy wings, and wx+ gives non-waxy. The allele cn ofa third gene gives cinnabar eyes, and cn+ gives red. A female heterozygous for these three genes istestcrossed, and 745 progenies are produced which are phenotypically classified as follows:5 b+ wx+ cn+4 b wx cn53 b+ wx cn 49 b wx+ cn+287 b+ wx+ cn279 b wx cn+ 33 b+ wx cn+35 b wx+ cn Make a linkage map of the three genes. Compute for interference and explain what the derived valuemeans. Show complete solutions to support your answers.
The production of eye-color pigment in Drosophila requires the dominant allele A. The dominant allele P of a second independent gene turns the pigment to purple, but its recessive allele leaves it red. A fly producing no pigment has white eyes. Two pure lines were crossed with the following results:P red-eyed female white-eyed maleF1 purple-eyed femalesred-eyed malesF1 F1purple eyed 38red eyed 38white eyed 28F both males and females: 2Explain this mode of inheritance, and show the genotypes of the parents, the F1, and the F2.
Assume that the genes for yellow body and mini wings are 35 map units apart on chromosome I in Drosophila. Assume also that a yellow-bodied female was mated to a mini-winged male and that the resulting F1 phenotypically wild-type females were mated to yellow-bodied, mini-winged males. Of 600 offspring, what would be the expected number of wild-type offspring? 210 195 105 390 The answer is NOT 195.
Male Drosophila expressing the autosomal recessivemutations sc (scute), ec (echinus), cv (crossveinless),and b (black) were crossed to phenotypically wildtype females, and the 3288 progeny listed wereobtained. (Only mutant traits are noted.)653 black, scute, echinus, crossveinless670 scute, echinus, crossveinless675 wild type655 black71 black, scute73 scute73 black, echinus, crossveinless74 echinus, crossveinless87 black, scute, echinus84 scute, echinus86 black, crossveinless83 crossveinless1 black, scute, crossveinless1 scute, crossveinless1 black, echinus1 echinusa. Diagram the genotype of the female parent.b. Map these loci.c. Do the data provide evidence of interference?Justify your answer with numbers.
F1 female Drosophila heterozygous for cinnabar eye (cn), vestigial wings (vg) and roof wings (rf) genes were test crossed with males homozygous for all three traits. The following result were obtained. 382 cinnabar, vestigial 401 roof 3 cinnabar 4 roof, vestigial 59 cinnabar, roof, vestigial 67 wild 44 cinnabar, roof 40 vestigial The chromosomal interference is equal to? 0.24 0.32 0.42 0.58 0.49
Drosophila females heterozygous for three recessive mutations, a, b, and c , were crossed to males homozygous for all three mutations.The cross yielded the following results: in the image Q. Construct a linkage map showing the correct order of these genes and estimate the distances between them.
In the fruit fly, Drosophila melanogaster, a spineless (no wing bristles) female fly ismated to a male that is claret (dark eyes) and hairless (no thoracic bristles).Phenotypically wild-type F1 female progeny were mated to fully homozygous (mutant)males, and the following progeny (1000 total) were observed: Phenotypes Number Observed spineless 321wild 38claret, spineless 130claret 18claret, hairless 309hairless, claret, spineless 32hairless 140hairless, spineless 12(a) Which gene is in the middle? (b) With respect to the three genes mentioned above, what are the genotypes of thehomozygous parents used in making the phenotypically wild F1 heterozygote? explain it. (c) What are the map distances between the three genes? explain it. (d) What is the coefficient of coincidence? explain it.
In Drosophila, a cross was made between females expressing thethree X-linked recessive traits, scute bristles (sc), sable body (s),and vermilion eyes (v), and wild-type males. All females were wildtype in the F1, while all males expressed all three mutant traits.The cross was carried to the F2 generation and 1000 offspringwere counted, with the results shown in the following table. Nodetermination of sex was made in the F2 data. Question:Calculate the coefficient of coincidence; does this represent positive or negative interference? Phenotype Offspringsc s v 314+ + + 280+ s v 150sc + + 156sc + v 46+ s + 30sc s + 10+ + v 14