Phosphorus may be determined analytically by precipitating it as MgNH4PO4 followed by ignition to Mg2P2O7. What mass of Mg2P2O7 will be obtained from a 9.346 g sample of phosphate rock which contains 71.24% Ca3(PO4)2?
Phosphorus may be determined analytically by precipitating it as MgNH4PO4 followed by ignition to Mg2P2O7. What mass of Mg2P2O7 will be obtained from a 9.346 g sample of phosphate rock which contains 71.24% Ca3(PO4)2?
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.87PAE
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Phosphorus may be determined analytically by precipitating it as MgNH4PO4 followed by ignition to Mg2P2O7. What mass of Mg2P2O7 will be obtained from a 9.346 g sample of phosphate rock which contains 71.24% Ca3(PO4)2?
Expert Solution
Step 1
Given data:
Mass of sample of phosphate rock = 9.346 gms
It contains 71.24% of Ca3(PO4)2
So, mass of Ca3(PO4)2 in sample rock =
Molar mass of Ca3(PO4)2 = 310.17 gms/mol
Mass of Phosphorous in Ca3(PO4)2 = 2 x 30.97 = 61.94 gms
So, mass of phosphorous in sample =
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