Phthalic acid ( H 2 C 8 H 40 4, abbreviated H 2 Ph ) is a diproticacid. Its ionization in water at 25°C takes place in twosteps: H 2 Ph (a q ) + H 20 (1)2H30+(aq) + HPh – ( a q ) Kal = 1.26 x 10 - 3 H 2 Ph - ( aq) +H 20 (1)2H30+( aq) + Ph 2 - (aq) Ka 2 = 3.10 × 10 – 6 If 0.0100 mol of phthalic acid is dissolved per liter ofwater, calculate the equilibriumconcentrations of H 2 Ph , H Ph-, Ph 2 -, and H 3 0 + .

Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter15: Solutions Of Acids And Bases
Section: Chapter Questions
Problem 15.54QE: Assuming that the conductivity of an acid solution is proportional to the concentration of H3O+,...
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Phthalic acid (H 2 C 8 H 4 O 4 , abbreviated H 2 Ph ) is a
diproticacid. Its ionization in water at 25°C takes place in
twosteps:
H 2 Ph ( a q ) + H 20 (1)2H 30+ ( a q ) + HPh – ( a q)
Ка1-1.26 х 10- 3Н2 Ph - (аq)+H20(1) нзо+(аq) + Ph
2 - (aq)
If 0.0100 mol of phthalic acid is dissolved per liter ofwater,
calculate the equilibriumconcentrations of H 2 Ph , H P h-, Ph
Ка 2-3.10х 10 - 6
2 -, and H 30 +.
Transcribed Image Text:Phthalic acid (H 2 C 8 H 4 O 4 , abbreviated H 2 Ph ) is a diproticacid. Its ionization in water at 25°C takes place in twosteps: H 2 Ph ( a q ) + H 20 (1)2H 30+ ( a q ) + HPh – ( a q) Ка1-1.26 х 10- 3Н2 Ph - (аq)+H20(1) нзо+(аq) + Ph 2 - (aq) If 0.0100 mol of phthalic acid is dissolved per liter ofwater, calculate the equilibriumconcentrations of H 2 Ph , H P h-, Ph Ка 2-3.10х 10 - 6 2 -, and H 30 +.
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