Physics Question #25: A jogger accelerates from rest to 3.0 m/s in 2.0 s. A car accelerates from 38.0 to 41.0 m/s also in 2.0 s. (a) Find the acceleration (magnitude only) of the jogger. (b) Determine the acceleration (magnitude only) of the car. (c) Does the car travel farther than the jogger during the 2.0 s ? If so , how much farther ?

Physics Question #25: A jogger accelerates from rest to 3.0 m/s in 2.0 s. A car accelerates from 38.0 to 41.0 m/s also in 2.0 s. (a) Find the acceleration (magnitude only) of the jogger. (b) Determine the acceleration (magnitude only) of the car. (c) Does the car travel farther than the jogger during the 2.0 s ? If so , how much farther ?

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter3: Motion Along A Straight Line

Section: Chapter Questions

Problem 2CQ: Under what circumstances does distance traveled equal magnitude of displacement? What is the only...

See similar textbooks

Similar questions

Under what circumstances does distance traveled equal magnitude of displacement? What is the only case in which magnitude of displacement and displacement are exactly the same?
A particle moves along the x axis according to the equation x = 2.00 + 3.00t 1.00t2, where x is in meters and t is in seconds. At t = 3.00 s, find (a) the position of the particle, (b) its velocity, and (c) its acceleration.
The position of a particle moving along the x axis varies in time according to the expression x = 3t2, where x is in meters and t is in seconds. Evaluate its position (a) at t = 3.00 s and (b) at 3.00 s + t. (c) Evaluate the limit of x/t as t approaches zero to find the velocity at t = 3.00 s.
On a one lane road, a person driving a car at v1 = 58 mi/h suddenly notices a truck 1.1 mi in front of him. That truck is moving in the same direction at v2 = 35 mi/h. In order to avoid a collision, the person has to reduce the speed of his car to v2 during time interval Δt. The smallest magnitude of acceleration required for the car to avoid a collision is a. During this problem, assume the direction of motion of the car is the positive direction. 1. Use the expressions you entered in parts (c) and (f) and enter an expression for a in terms of d, v1, and v2. a = ( v2 - v1 )/Δt Δt = ( 2 ) ( d )/( v1 - v2 ) 2. Calculate the value of a in meters per second squared.
At an air show, a jet plane has velocity components vx= 695km/h and v y =415km/h at time 4.35 s and v x =938km/h and V y =365km/h at time 7.52s. A)For this time interval, find the xxx component of the plane's average acceleration. b)For this time interval, find the yyy component of the plane's average acceleration. C)For this time interval, find the magnitude of its average acceleration. D)For this time interval, find the direction of its average acceleration.
An unidentified flying object (UFO) is observed to travel a total distance of 19000 m, starting and ending at rest, over a duration of 4.23 s. Assuming the UFO accelerated at a constant rate to the midpoint of its journey and then decelerated at a constant rate the rest of the way, what was the magnitude of its acceleration? Express your answer in g s , where 1 g = 9.81 m/s^2.
A jet plane comes in for a landing with a speed of 100m/s, and its acceleration can have a maximum magnitude of 5.00m/s2 as it comes to rest from the instant the plane touches the runway, what is the minimum time interval needed before it can come to rest?
In a friendly game of chicken, Car A has a starting distance of 160m in front of Car B. Both cars start with the same speed of 100 km/h, and both cars accelerate at constant rates. Knowing that Car B accelerates at 4.25 m/s^2. And car A accelerates at 4.00 m/s^2 . Determine the position in meters, that they crash.
Immediately as a traffic light turns green, a car speeds up from rest, accelerating at a rate of 2m/s/s as it travels 150m. How fast is the car moving after this is done? (Kinematics equation 3) A.26.3 m/s B.24.5 m/s C.26.8 m/s D.25.9 m/s
In a marathon race Chad is out in front, running due north at a speed of 4.03 m/s. John is 97 m behind him, running due north at a speed of 4.70 m/s. How long does it take for John to pass Chad?
A jetliner, travelling northward, is landing with a speed of 69 m/ s. Once the jet touches down, it has 750 m of runway in which to reduce its speed to 6.1 m/ s. Compute the average acceleration (magnitude and direction) of the plane during landing.
The following equations give the position x(t) of a particle in four situations (in each equation, x is in meters, tis in seconds, and t> 0): (1) x = 3t - 4: (2) x = -5t3 + 4t2 + 6: (3) x = 2/t2 - 4/t; (4) x = 5t2 3. (a) In which situation is the acceleration a of the particle constant?