00 LL I 10 m toward the WEST. 60 m toward the WEST. 0 m. 50 m toward the WEST. 20 m toward the WEST. < Prev 22 of 25 search 91 f12 4- Ins prt sc LLJ 114 04 delete 144 home 24 backspace num lock | P. H. enter asned shift WIN8 工 A runner runs 10 m from the origin toward the WEST to point A. He then runs from point A 20 m more toward the WEST to point B. He then runs from point B 30 m more toward the WEST to point C. The runner's total displacement from the origin to point C is Multiple Choice 10 m toward the WEST. 60 m toward the WEST. 0m. 50 m toward the WEST < Prev 22 of 25 Co search 近0 75°F dy f12 ins prt sc LL + eリ delete 114 o14 home 144 %24 4. backspace 8. unu lock D. enter osned 1shift WN A alt ctri

00 LL I 10 m toward the WEST. 60 m toward the WEST. 0 m. 50 m toward the WEST. 20 m toward the WEST. < Prev 22 of 25 search 91 f12 4- Ins prt sc LLJ 114 04 delete 144 home 24 backspace num lock | P. H. enter asned shift WIN8 工 A runner runs 10 m from the origin toward the WEST to point A. He then runs from point A 20 m more toward the WEST to point B. He then runs from point B 30 m more toward the WEST to point C. The runner's total displacement from the origin to point C is Multiple Choice 10 m toward the WEST. 60 m toward the WEST. 0m. 50 m toward the WEST < Prev 22 of 25 Co search 近0 75°F dy f12 ins prt sc LL + eリ delete 114 o14 home 144 %24 4. backspace 8. unu lock D. enter osned 1shift WN A alt ctri

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter4: Motion In Two And Three Dimensions

Section: Chapter Questions

Problem 21P: A cyclist rides 5.0 km due east, then 10.0 km 20 west of north. From this point she rides 8.0 km due...

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A hiker starts at his camp and moves the following distances while exploring his surroundings: 75.0 m north, 2.50 102 m east, 125 m at an angle 30.0 north of east, and 1.50 102 m south. (a) Find his resultant displacement from camp. (Take east as the positive x-direction and north as the positive y-direction.) (b) Would changes in the order in which the hiker makes the given displacements alter his final position? Explain.
Do Exercise 3.16 again using analytical techniques and change the second leg of the walk to 25.0 m straight south. (This is equivalent to subtracting B from A —that is, finding R=AB ) (b) Repeat again, but now you first walk 25.0 m north and then 18.0 m east. (This is equivalent to subtract A from B —that is, to find A=B+C. Is that consistent with your result?)
A snow-covered ski slope makes an angle of 35.0 with the horizontal. When a ski jumper plummets onto the hill, a parcel of splashed snow is thrown up to a maximum displacement of 1.50 m at 16.0 from the vertical in the uphill direction as shown in Figure P3.16. Find the components of its maximum displacement (a) parallel to the surface and (b) perpendicular to the surface. Figure P3.16
A delivery man starts at the post office, chives 40 km north, then 20 km west, then 60 km northeast, and finally 50 km north to stop for lunch. Use a graphical method to find his net displacement vector.
Vector A has x and y components of 8.70 cm and 15.0 cm, respectively; vector R has x and y components of 13.2 cm and 6.60 cm, respectively. If AB+3C=0, what are the components of C?
What is the gardeners displacement (Fig. 2.21)? Give a general direction, such as south or west. (Hint: Think of a 3-4-5 triangle, Pythagorean theorem.) Figure 2.21 A Walk through the Garden See Exercises 1 and 2.
A cyclist rides 5.0 km due east, then 10.0 km 20 west of north. From this point she rides 8.0 km due west. What is the final displacement from where the cyclist started?
(a) Repeat the problem two problems prior, but for the second leg you walk 20.0 m in a direction 40.0° north of east (which is equivalent to subtracting B from A that is, to finding R=AB ). (b) Repeat the problem two problems prior, but now you first walk 20.0 m in a direction 40.0° south of west and then 12.0 m in a direction 20.0° east of south (which is equivalent to subtracting A from B that is, to finding R=BA=R ). Show that this is the case.
A hiker walks 22.93 m at 26.74 degrees. What is the X component of his displacement?
Problem 1:A man sailing a boat follows the directions to a dock. The instructions stated that he hasto sail 25.0 m in a direction 60º E of N from his starting location, and then sail additional35.0 m in a direction 50º E of S. How far will he be from his starting point?Problem 2:Suppose a pilot flies 15.0 km in a direction 60º N of E and then flies 30.0 km in a direction15º N of E. Find the total distance R from the starting point and the direction θ of thestraight-line path to the final position.
An airplane travels 200 km, 30 degrees NE. It changes its course by moving 100 km north before reaching its destination. Using the laws of sine and cosine, determine the resultant displacement of the airplane.
Suppose you first walk 12.0 m in a direction 20º west ofnorth and then 20.0 m in a direction 40.0º south of west.How far are you from your starting point, and what is thecompass direction of a line connecting your starting point toyour final position? (If you represent the two legs of the walkas vector displacements A and B , thenthis problem finds their sum R = A + B .)