oke DR LIV y=Y3 y=Y₂ Y₁=0 = Because of the foamy nature of the fluid, its density is significantly less than the density of water. We'll assume that the density of the foam is p = 430.0 kg/m³. The height of the coke bottle is y2 0.306 meters, and the maximum height reached by the foam is y3 = 1.546 meters. We'll do our analysis using absolute pressure, and so we conclude that at the places where the fluid touches air (y2 and y3) it has the same pressure as the air, namely 101300 Pascals. We will furthermore, treat the bottle as a "tank" so that the fluid velocity at the bottom of the bottle is zero. Finally, we note that the opening of the bottle is circular with a radius of 0.014 meters. Determine all the following: The absolute pressure at the bottom of the coke bottle: P = The velocity of the fluid as it exits the bottle: v₂ = The mass rate of flow (kg/sec) leaving the bottle: m/s kg/sec Pascals

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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oke
DR
LIV
y=Y3
y=Y₂
Y₁=0
Transcribed Image Text:oke DR LIV y=Y3 y=Y₂ Y₁=0
=
Because of the foamy nature of the fluid, its density is significantly less than the density of water. We'll assume that the
density of the foam is p = 430.0 kg/m³. The height of the coke bottle is y2 0.306 meters, and the maximum height
reached by the foam is y3 = 1.546 meters. We'll do our analysis using absolute pressure, and so we conclude that at the
places where the fluid touches air (y2 and y3) it has the same pressure as the air, namely 101300 Pascals. We will
furthermore, treat the bottle as a "tank" so that the fluid velocity at the bottom of the bottle is zero. Finally, we note that the
opening of the bottle is circular with a radius of 0.014 meters.
Determine all the following:
The absolute pressure at the bottom of the coke bottle: P =
The velocity of the fluid as it exits the bottle: v₂ =
The mass rate of flow (kg/sec) leaving the bottle:
m/s
kg/sec
Pascals
Transcribed Image Text:= Because of the foamy nature of the fluid, its density is significantly less than the density of water. We'll assume that the density of the foam is p = 430.0 kg/m³. The height of the coke bottle is y2 0.306 meters, and the maximum height reached by the foam is y3 = 1.546 meters. We'll do our analysis using absolute pressure, and so we conclude that at the places where the fluid touches air (y2 and y3) it has the same pressure as the air, namely 101300 Pascals. We will furthermore, treat the bottle as a "tank" so that the fluid velocity at the bottom of the bottle is zero. Finally, we note that the opening of the bottle is circular with a radius of 0.014 meters. Determine all the following: The absolute pressure at the bottom of the coke bottle: P = The velocity of the fluid as it exits the bottle: v₂ = The mass rate of flow (kg/sec) leaving the bottle: m/s kg/sec Pascals
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