Part A:
From the given graph we can see that the velocity of the body remains constant from
t = 0 s to t = 3 s which means the acceleration is Zero.
From the given graph we can see that the velocity (V) of the is 3 m/s from t1 = 0 s to t2 = 3 s
Hence the displacement (S) is given by:
S = V × (t2 – t1)
S = 3 × 3
S = 9 m
From the given graph we can see that the velocity of the body at t2 = 3 s is, initial velocity (U), 3 m/s. ...
Image Transcriptionclose
V U 7-3 1.33 m/s2 a = 6-3 t3 t2 Then the displacement is given by the 2nd equation of motion as follows: =u(t3- t2)a(t3 - t4)2 Substituting the corresponding values, we get: S 22.64 m
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