Pinworm infestation, commonly found in children, can be treated with a drug that is effective in 92% of cases. Suppose (a) through (g) below. H Supposing a success s is that the child is cured, the success probability p is 0.92. OB. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has two possible outcomes, either cured or not cured. The results are dependent or other results. Supposing a success s is that the child is cured, the success probability p is OC. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has three possible outcomes, which are cured, not cured, or partially cured. The resu are independent. Supposing a success s is that the child is cured, the success probability p is. OD. Each trial consists of observing whether the child is not cured of the pinworm infestation by the drug and has two possible outcomes, either not cured or cured. The results are independent. Supposing a success s is that the child is not cured, the success probability p is. b. Construct a table that gives the probability for each outcome. (Let s be a success and f be a fakture.) Outcome Probability sss ssf sfs sff fss fsf

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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Pinworm infestation, commonly found in children, can be treated with a drug that is effective in 92% of cases. Suppose that three children with pinworm infestation are given the drug. Complete parts
(a) through (g) below.
Supposing a success s is that the child is cured, the success probability p is 0.92.
OB. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has two possible outcomes, either cured or not cured. The results are dependent on
other results. Supposing a success s is that the child is cured, the success probability p is
cured, not cured, or partially cured. The results
OC. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has three possible outcomes, which
are independent. Supposing a success s is that the child is cured, the success probability p is.
forre
OD. Each trial consists of observing whether the child is not cured of the pinworm infestation by the drug and has two possible outcomes, either not cured or cured. The results are independent.
Supposing a success s is that the child is not cured, the success probability p is
Outcome
Probability
b. Construct a table that gives the probability for each outcome. (Let s be a success and f be a fakture.)
sss
ssf
sfs
sff
fss
fsf
ffs
fff
(Round to three decimal places as needed.)
@
#
$
%
A
2
3
4
5
6
9
tab
1
Q
W
E
R
T
Y
&
7
U
+00
8
O
Transcribed Image Text:Pinworm infestation, commonly found in children, can be treated with a drug that is effective in 92% of cases. Suppose that three children with pinworm infestation are given the drug. Complete parts (a) through (g) below. Supposing a success s is that the child is cured, the success probability p is 0.92. OB. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has two possible outcomes, either cured or not cured. The results are dependent on other results. Supposing a success s is that the child is cured, the success probability p is cured, not cured, or partially cured. The results OC. Each trial consists of observing whether the child is cured of the pinworm infestation by the drug and has three possible outcomes, which are independent. Supposing a success s is that the child is cured, the success probability p is. forre OD. Each trial consists of observing whether the child is not cured of the pinworm infestation by the drug and has two possible outcomes, either not cured or cured. The results are independent. Supposing a success s is that the child is not cured, the success probability p is Outcome Probability b. Construct a table that gives the probability for each outcome. (Let s be a success and f be a fakture.) sss ssf sfs sff fss fsf ffs fff (Round to three decimal places as needed.) @ # $ % A 2 3 4 5 6 9 tab 1 Q W E R T Y & 7 U +00 8 O
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