Plate A, PL 16mm x 375mm, is connected to another plate B with 10-22 mm p bolts as shown. The steel is A36 steel with Fy= 250 MPa and Fu= 400 MPa. Assume that plate B has adequate strength. Use ASD. Plate B 37.5mm 75mm 75mm Plate A 75mm 75mm 37.5mp ↑ 150 50 50 mammird
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- A single-angle tension member 175 mm x 100 mm x 18 mm haw two gage lines in its long leg and one in the short leg for 16 mm bolts arranged as shown. Area of the angular section is 4961 mm^2. Use A36 steel Fy = 248 MPa and Fu = 400 MPa. Standard nominal hole diameter for 16 mm bolt = 17 mm. Determine the net area of the angular section. Determine the allowable tension strength of the angular section based on the gross area. Determine the allowable tensile strength of the angular section based on the effective net area. Reduction factor U = 0.75The 1 × 8 plate is shown in the figure. The holes are for 3/4-in Ø bolts. Compute the net area of each of the given members. (Ans. 6.44 in^2)An L6 × 6 × 1/2 is used as a tension member, with one gage line of 3/4-in Ø bolts in each leg at the usual gage location (see Table 3.1). What is the minimum amount of stagger, s, necessary so that only one bolt need be subtracted from the gross area of the angle? Compute the net area of this member if the lines of holes are staggered at 3 in. (Ans. s=4.77 in, An = 5.05 in^2)
- Bottom chord of truss is composed of two angle bars each having a dimension of 151 mm x 198 mm x 7 mm. Between them is a gusset plate, 9.5mm thick. At each end of joints, four 19mm-dia. bolts are fastened along the gage line, having an edge distance of 38 mm and 55.8mm pitch. Use A36 steel Fy = 248 MPa Fu = 400 MPa spacing of bolt = 67.3 mm Compute the capacity of the bottom chord based on block shear strength, in KN.an angle bar 100x100x11 mm tension member is connected with 20-mm-dia bolts as shown in the fig. both legs of the angles are connected. use fy=248 MPa and Fu=400 MPa. 1. determine the nominal strength for tensile yielding in the gross section. a. 515.59 kN b. 429.67 kN c. 545.60 kN d. 390.10 kN 2. determine the effective net area of member a. 1573 mm^2 b. 1632 mm^2 c. 1605 mm^2 d. 1815 mm^2 3. determine the nominal strength for tensile rupture in the net area. a. 642 kN b. 730 kN c. 554 kN d. 650 kNGIVEN: PL ⅜ x 5 ½ of A242 steel ⅜ - inch thick gusset plate A242 steel ¾ - inch diameter bolts REQUIRED: The nominal block shear strength of the tension member
- Determine the effective net area using the U values given on Table 3.2 An MC12x45 is connected through its web with 3 gages lines of 22mm diameter bolts. The gage lines are 76mm on center and the bolts are spaced 80mm on center along the gage line. If the center row of bolt is staggered with respect to the outer row, determine the effective net cross-sectional area of the channel. Assume there are four bolts in each line. Draw the figure first and label it properly. Draw the fracture path using different color or line weights.An L 150 x 100 x 16 is used as a tension member, with one gage line of 20 mm bolts in each leg at the usual gage location (Table3.1, where g=60 mm, g1=55 mm, and g2=60mm). Two rows of bolts are used in the long leg, and one in the short leg. What is the net area of the given steel connection? Stagger, s=58.63mm (Key Answer: An=3,008.00 mm)Calculate the capacity of the shear connection below. A36 Plate: Fyp= 248MPa, Fup= 400MPa. A992 Beam; Fyb= 345MPa, Fub= 450MPa. Fexx= 480MPa. twb= 10.92mm tp= 12, X= 45, nr= 3(no. of bolts) What is the bolt shear capacity in kN? What is the bearing capacity of the shear plate in kN? What us the bearing capacity of the beam in kN? What is the shear yielding capacity of shear plate in kN? What is the shear rupture capacity of the shear plate in kN? What is the block shear rupture capacity of shear plate in kN? What is the weld capacity in kN?
- A 1 ⁄2 × 5-inch plate of A588 steel is used as a tension member. It is connected to a gusset plate with four 5 ⁄8-inch-diameter bolts as shown in Figure 1. Assume that the effective net area Ae equals the actual net area An. (a) Calculate the design strength for LRFD? (b) Calculate the allowable strength for ASD?3.6-5 Use load and resistance factor design and select an American StandardChannel shape to resist a factored tensile load of 180 kips. The length is15 ft, and there will be two lines of 7⁄8-in. diameter bolts in the web, asshown in Figure P3.6-5. Estimate the shear lag factor U to be 0.85. (In apractical design, once the member and bolt layout are selected, the valueof U could be computed and the member design could be revised if necessary.)Use A36 steel.A channel shape, C8 × 18.75, is used as a tension member. The channels are boltedto a 10mm-thick gusset plate with 22mm- diameter bolts. The tension member is A572 Grade 50 steel (Fy = 345 MPa, Fu = 450 MPa) and the gusset plate is A36 (Fy = 250 MPa, Fu = 410MPa). What is the ult. capacity of the gusset plate in kips, if block shear governs? What is the effective net area of the channel section, in square millimeters?