Please draw Datapath and list the local storage with minimum numbers of bits
Q: A timing diagram for Direct Memory Access (DMA) with clock synchronisation?
A: Memory on the computer: It is the location where task-related data and procedures are kept and…
Q: 11. For the ROM array in Figure 11-79, determine the outputs for all possible input combinations,…
A: Given:
Q: Define demand-zero memory
A: GIVEN: Define demand-zero memory
Q: 12. Determine the truth table for the ROM in Figure 11-80. Address decoder 2 Ag 3 A1 A2 7 FIGURE…
A:
Q: Design a 8x4 ROM with the following contents. Show the full diagram and follow all the required…
A: GIVEN:
Q: 12. Assume register [0x23] = 0x49, STATUS carry bit is 0, execute “RLCF 0x23, W, A", what values…
A: Given The answer is given below.
Q: Identify the addressing modes used for the source and destination operands, and then compute the…
A: Given: We are given an instruction that contains various fields such as opcode, and operands. Goal:…
Q: B. Determine the Logical and Physical Addresses and the lower and upper ranges if DS-2000H, SI-400H.…
A: Given Data segment DS = 2000H , SI = 400H Note : the above values are hexa decimal values. We have…
Q: Design a 16-bit ALU from scratch following ISA format with a control unit in Logisim with…
A: Answer: I have given answered in the handwritten format
Q: 3. Given the data 0×123456789ABC and the starting location (lowest address) of data memory (0x018)…
A: GIVEN:
Q: rue/False During the 'READ' of the SRAM structure studied in the class, the bit and bit_bar are…
A: let us see the answer:- The correct answer is true:-
Q: Q#02) Explain Direct Memory Access (DMA), and Input/output timing diagram with clock…
A: Direct memory access (DMA) is a mode of data transfer between the memory and I/O devices. This…
Q: * CMP C will Compare the contents of register B and Register C Compare the contents of register E…
A: We are given an instruction CMP C and we are asked what happened when we execute it. I have…
Q: Develop an ALP to transfer the content of ROM location starting from 300H to RAM location 50H. After…
A: SUMMARY: - Hence, We discussed all the points
Q: b) Binary values of the select inputs S2, S1, and So that must be applied to BUS;
A: The question is to write the answer of question b) for the given problem.
Q: 5. Use the Design Procedure to design a device that will change serial data to parallel data, :
A: The Answer is in given below step
Q: Write an ALP to copy 4 bytes of data from memory location 2500h to 3500h
A: Program 1: LDA 2500H : "Get the contents of memory location 2500H into accumulator"MOV B, A :…
Q: You are required to design address decoding table for all devices above
A: ANSWER: Address Decoding Table: The processor can ordinarily address a memory space that is a lot…
Q: Ql: Assume we have a CP register is 16 bits length and the Register File has two read ports and one…
A: The diagram is in the next step:
Q: Describe Direct Memory Access (DMA), as well as an input/output timing diagram with clock…
A: Computer memory: It is the place where data and procedure to perform task is stored and maintained…
Q: The idle state is one clock period long, is inserted in the the bus cycle, while the wait state…
A: Lets see the solution.
Q: State the differences between write bus cycle in memory in and read in Input/Output.
A: State the differences between write bus cycle in memory in and read in Input/Output.
Q: Write three address code and quadruple for the expression a[i] = -b * (a[k--] – y[ k--] /2)
A: Three-address code is the intermediate code that is used by the optimizer compiler by breaking down…
Q: List the sequence of events for the indexed addressing mode.
A: Indexed addressing mode: It is utilized by the instruction that consists of the mnemonic op-code…
Q: In ROM, the data bus is not Unidirectional Select one: O True O False
A: Question. In ROM, the data bus is not unidirectional.
Q: Calculate the number of entries in page table for a virtual memory of MIPS with 20 KB page size.
A: The page table entry consists of various information about the page. The information consists in the…
Q: 5. For in-use inodes, each address in use is also marked in use in the bitmap. If not, print ERROR:…
A: The above question is solved in step 2:-
Q: Explain Direct Memory Access (DMA), and Input/output timing diagram with clock synchronization
A: Direct Memory Access (DMA): Direct Memory Access transfers the block of data between the memory…
Q: A particular SDRAM system uses 24-bit addresses. There are 2 ranks in the system and the burst…
A: Solution:-- 1)The given question has required for the solution to be provided with purpose of the…
Q: Write three address code and quadruple for the expression a[i] = -b * (a[k--]- y[ k--] /2)
A: a[I]=-b*(a[k--]-y[k--]/2)
Q: Please write an introduction and conclusion for your lap report on data transmission with external…
A: Introduction to External Memory Data TransferData is sent between the microprocessor and I/O devices…
Q: Write down the control sequence for the following instructions (given as operation source…
A: Task : Write the control sequence for the given instructions.
Q: Question 1. See the next 8-4-2-1 code for the decimal numbers 0 to 9. Design the next different…
A: The, answer has given below:
Q: 3. Show the inputs and outputs for a 128 MByte memory with 32-bit read/write operations and byte…
A: The diagram is drawn in the next step :
Q: (B)- Identify the addressing modes used for the source and destination operands, and then compute…
A: Address modes of 8085:
Q: Draw the complete design for constructing a SRAM memory of a total capacity 512KX32 using a SRAM…
A: Draw the complete design for constructing a SRAM memory of a total capacity 512k * 32 using a SRAM…
Q: QUESTION 42 The second half of the DRAM address is stored by activating the CAS (column address
A: The given question is as a written below- The second half of the DRAM address is stored by…
Q: Draw the functional block diagram of the datapath unit.
A: Functional block diagram:
Q: 2 - Memory Read causes data: from the addressed location to be placed on the data bus on the bus to…
A: The corresponding memory chip or I/O device is selected by a decoding circuit. Memory requires some…
Q: Assume that in the system of the preceding problem, a memory cycle takes 750 ns. To what value could…
A:
Q: with 20address lines, up to 2MB of memory can be addressed 1-true 2-false
A: 20 address lines are needed for 1MB of Data. Lets calculate other way around No Of address lines 20,…
Q: Show the contents of a lookup ROM which implements the function (X -3). X and Y are 3-bit values. X…
A: The required look-up table with given below, with intermediate steps (x+1 and y+1) shown in there.…
Q: Calculate the number of entries in page table for a virtual memory of MIPS with 10 KB page size.
A: Solution Plan There are two types of MIPS architecture 32 bits and 64 bits. Calculate the number…
Q: are used to over come the difference in data transfer speeds of various devices. a. Speed enhancing…
A: Required: ______ are used to over come the difference in data transfer speeds of various…
Q: Give one example for each of the addressing modes.
A: Addressing modes are only the various manners by which the area of an operand can be indicated in a…
Q: 3. Given the data O×123456789ABC and the starting location (lowest address) of data memory (0x018)…
A: The answer is given below For the above given question:
Q: What is the difference between the operation of programmed I/O and DMA?
A: An operating system is a program that serves as a link between the user and the computer equipment,…
Q: this: For register RO to R63 in a 16-bit bus system; what is the MUX size we use? and how many…
A:
Q: 2. If physical address of data in the data segment is F3124H and the offset address in register SI =…
A: Memory addressing schemes:1. An Absolute Address, such as 04A26H, is a 20-bit number that refers to…
Q: MP store the higher order 8bit and lower order 8bit of the address in the Z and W registers,…
A: According to the information given:- We have to choose the correct option to satisfy the situation
Please draw Datapath and list the local storage with minimum numbers of bits
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- in Python Minima in permutations. Write a program that takes an integer n from the command line, generates a random permutation, prints the permutation, and prints the number of left-to-right minima in the permutation (the number of times an element is the smallest seen so far). Then write a program that takes integers m and n from the command line, generates m random permutations of length n, and prints the average number of left-to-right minima in the permutations generatedAdd comments in code #include <stdio.h>#include <stdlib.h>/* ADJACENCY MATRIX */int source,V,E,time,visited[20],G[20][20];void DFS(int i){ int j; visited[i]=1; printf(" %d->",i+1); for(j=0;j<V;j++) { if(G[i][j]==1&&visited[j]==0) DFS(j); }}int main(){ int i,j,v1,v2; printf("\t\t\tGraphs\n"); printf("Enter the no of edges:"); scanf("%d",&E); printf("Enter the no of vertices:"); scanf("%d",&V); for(i=0;i<V;i++) { for(j=0;j<V;j++) G[i][j]=0; } /* creating edges :P */ for(i=0;i<E;i++) { printf("Enter the edges (format: V1 V2) : "); scanf("%d%d",&v1,&v2); G[v1-1][v2-1]=1; } for(i=0;i<V;i++) { for(j=0;j<V;j++) printf(" %d ",G[i][j]); printf("\n"); } printf("Enter the source: "); scanf("%d",&source); DFS(source-1); return 0;}If you cube each integer in turn from 10 to one million, you will see that 11 of them produce a result that is a palindrome (the same forwards as backwards). For example, 11×11×11=133111×11×11=1331. Write a single line of code to produce those 11 numbers and their cubes in a list of tuples.
- Correct answer will be upvoted else Multiple Downvoted. Don't submit random answer. Computer science. Ridbit begins with an integer n. In one action, he can perform one of the accompanying tasks: partition n by one of its appropriate divisors, or take away 1 from n in case n is more prominent than 1. An appropriate divisor is a divisor of a number, barring itself. For instance, 1, 2, 4, 5, and 10 are appropriate divisors of 20, however 20 itself isn't. What is the base number of moves Ridbit is needed to make to decrease n to 1? Input The principal line contains a solitary integer t (1≤t≤1000) — the number of experiments. The main line of each experiment contains a solitary integer n (1≤n≤109). Output For each experiment, output the base number of moves needed to lessen n to 1.Add comments in code to explain #include <stdio.h>#include <stdlib.h>/* ADJACENCY MATRIX */int source,V,E,time,visited[20],G[20][20];void DFS(int i){ int j; visited[i]=1; printf(" %d->",i+1); for(j=0;j<V;j++) { if(G[i][j]==1&&visited[j]==0) DFS(j); }}int main(){ int i,j,v1,v2; printf("\t\t\tGraphs\n"); printf("Enter the no of edges:"); scanf("%d",&E); printf("Enter the no of vertices:"); scanf("%d",&V); for(i=0;i<V;i++) { for(j=0;j<V;j++) G[i][j]=0; } /* creating edges :P */ for(i=0;i<E;i++) { printf("Enter the edges (format: V1 V2) : "); scanf("%d%d",&v1,&v2); G[v1-1][v2-1]=1; } for(i=0;i<V;i++) { for(j=0;j<V;j++) printf(" %d ",G[i][j]); printf("\n"); } printf("Enter the source: "); scanf("%d",&source); DFS(source-1);…I want to convert this method to search by first letter instead of the full name (for example if the user enter F it shows all node that have F letter in its name ) public void search() { int flag = 0; Node pointer; System.out.print("Enter the name you want to search: "); String key = input.next(); pointer = root; while (pointer != null) { if (pointer.name.compareTo(key) == 0) { flag = 1; System.out.println("RECORD FOUND"); System.out.println(); System.out.println("--------------------------"); System.out.println("NAME\t| CONTACT NUMBER "); System.out.println("--------------------------"); System.out.println("" + pointer.name + "\t " + pointer.number); System.out.println("------------------------"); break; } if ((pointer.name).compareTo(key) > 0) { pointer = pointer.left; } else { pointer = pointer.right; } } if (flag == 0) { System.out.println("RECORD NOT FOUND"); } }
- Write a program that replaces words in a sentence. The input begins with word replacement pairs (original and replacement). The next line of input is the sentence where any word on the original list is replaced. Ex: If the input is: automobile car manufacturer maker children kids The automobile manufacturer recommends car seats for children if the automobile doesn't already have one. the output is: The car maker recommends car seats for kids if the car doesn't already have one. You can assume the original words are unique. Code: def main():replacement_pairs = input()replacement_pairs = replacement_pairs.split()original = []replacement = []for i in range(len(replacement_pairs)):if i % 2 == 0:original.append(replacement_pairs[i])else:replacement.append(replacement_pairs[i])sentence = input()sentence = sentence.split()for i in range(len(sentence)):for j in range(len(original)):if(sentence[i] == original[j]):sentence[i] = replacement[j]for i in range(len(sentence)):print(sentence[i],…Write a program that replaces words in a sentence. The input begins with word replacement pairs (original and replacement). The next line of input is the sentence where any word on the original list is replaced. Ex: If the input is: automobile car manufacturer maker children kids The automobile manufacturer recommends car seats for children if the automobile doesn't already have one. the output is: The car maker recommends car seats for kids if the car doesn't already have one. You can assume the original words are unique. Code: def main():replacement_pairs = input()replacement_pairs = replacement_pairs.split()original = []replacement = []for i in range(len(replacement_pairs)):if i % 2 == 0:original.append(replacement_pairs[i])else:replacement.append(replacement_pairs[i])sentence = input()sentence = sentence.split()for i in range(len(sentence)):for j in range(len(original)):if(sentence[i] == original[j]):sentence[i] = replacement[j]for i in range(len(sentence)):print(sentence[i],…Write a program that replaces words in a sentence. The input begins with word replacement pairs (original and replacement). The next line of input is the sentence where any word on the original list is replaced. Ex: If the input is: automobile car manufacturer maker children kids The automobile manufacturer recommends car seats for children if the automobile doesn't already have one. the output is: The car maker recommends car seats for kids if the car doesn't already have one. You can assume the original words are unique. Code: def main():replacement_pairs = input()replacement_pairs = replacement_pairs.split()original = []replacement = []for i in range(len(replacement_pairs)):if i % 2 == 0:original.append(replacement_pairs[i])else:replacement.append(replacement_pairs[i])sentence = input()sentence = sentence.split()for i in range(len(sentence)):for j in range(len(original)):if(sentence[i] == original[j]):sentence[i] = replacement[j]for i in…
- ### Import section# 3 necessary statements for numerical plotting in Jupyterimport numpy as npimport matplotlib.pyplot as plt %matplotlib inline# Factorial comes from 'math' packagefrom math import factorial ### Initialization section#array of derivatives at 0 compute by handderiv = np.array([1, 0, -1, 0, 1, 0, -1, 0])# degree of Taylor polynomialN=len(deriv)-1 # Max abs. value of N+1 deriv on interval (Compute using calculus)# (used in the remainder formula)# @@@ The N+1 derivative will be proportional to cosine, and |cos| is always # @@@ less than 1maxAbsNplus1deriv=1 #array with h valuesh = np.arange(-3,3.005,0.01) # Give the expansion point for the Taylor seriesexpansion=0 # Create an array to contain Taylor seriestaylor = np.zeros(len(h)) ### Calculation section#calculate Taylor series for all h at once using a loopfor n in range(N+1): taylor = taylor + (h**n)/factorial(n)*deriv[n] #actual function values actualFn = np.cos(expansion+h) #error actual and taylor…Using Javascript Write a higher-order function that when given an array of numbers, return a new array that only includes the even numbers. Hint: filter() function evensOnly(arr) { // your code here}// testconsole.log(evensOnly([3, 5, 6, 8, 2, 11])); /// [6, 8, 2]Write a program that replaces words in a sentence. The input begins with word replacement pairs (original and replacement). The next line of input is the sentence where any word on the original list is replaced. Ex: If the input is: automobile car manufacturer maker children kids The automobile manufacturer recommends car seats for children if the automobile doesn't already have one. the output is: The car maker recommends car seats for kids if the car doesn't already have one. You can assume the original words are unique. My Code: def main():replacement_pairs = input()replacement_pairs = replacement_pairs.split()original = []replacement = [] for i in range(len(replacement_pairs)):if i % 2 == 0:original.append(replacement_pairs[i])else:replacement.append(replacement_pairs[i])sentence = input() sentence = sentence.split() for i in range(len(sentence)):for j in range(len(original)):if(sentence[i] == original[j]):sentence[i] = replacement[j]for i in range(len(sentence)):print(sentence[i],…