Please is there any other way to write the line l = [x for x in l if x not in n] and write the code another way ? Please help me on python without using "break" or "continue", and no global variables in functions. def remove_pairs(1):(list of str)->list of strReturns a copy of list 1 where all the pairs from 1 are removed ANDthe elements of the new list shuffledPrecondition: elements of 1 are cards represented as strings described aboveTesting:Note that for the individual calls below, the function shouldreturn the displayed list but not necessarily in the order given in the examples.>>> remove_pairs(['94', '54',['104', '24', '3♡',>>> remove_pairs(['104'['24', '50','44''54', '7♡', 'A^', '104', 'Q♡', '8♡'.190', '100'J♡', '10♡','J h', '3♡'])'KO', 'A','A',6','KO','J4', 'Q0']'AO','24', 'Q*', 'KA', 'Qo', 'Jª', 'A♡','44','7♡','80',194','24', '50','AO'j'100'])'6', '94'no_pairs=[]for i in ('2','3','4','5','6','7','8','9','10','J','Q','K','A'):n = []for j in range (len(1)):if 1[j].find (i) != -1:n.append (1[j])if len(n) == 2 or len(n) == 3:1.remove (n[0])1.remove (n[1])elif len(n) == 4:1 = [x for x in 1 if x not in n]no_pairs = 1random. shuffle(no_pairs)return no_pairs

The remоve() methоd remоves the first оссurrenсe оf the element with the sрeсified…

Please is there any other way to write the line l = [x for x in l if x not in n] and write the code another way ? Please help me on python without using "break" or "continue", and no global variables in functions.

Please is there any other way to write the line l = [x for x in l if x not in n] and write the code another way ? Please help me on python without using "break" or "continue", and no global variables in functions.

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter17: Linked Lists

Section: Chapter Questions

Problem 18PE

See similar textbooks

Similar questions

Sets are collections (1) without defined order and (2) not allowing duplication. Multisets, also called “bags” are collections without defined order but which permit duplication, i.e., more than one element. We define the function #(a B) to be the number of occurrences of the element a in the bag B. For example, #(1, [1 1 2 3 4 4 5]) is 2 and #(5, [1 1 2 3 4 4 5]) = 1. sum : List × List -> List This function should take as arguments two lists representing bags and should return the list representing the list resulting from simply appending the input lists together. Racket code only please. No loops Allowed: 1. define, let2. lambda, curry3. cons, car, cdr, list, list?, append, empty?, length, equal?4. and, or, not5. if, cond6. map, append-map, andmap, ormap, filter, apply7. +, -, /, * Thank you!
Merge2AscListsRecur that combines the nodes in X-list and Y-list into Z-list such that, after calling the function, Z-list is a sorted list (in non-decreasing order) containing all the nodes initially contained in X-list and Y-list – X-list and Y-list should both be empty after the call. The function should: ► Have only three parameters (each a pointer-to-Node) and no return value (be a void function). ► Not use any global variables or static local variables. ► Not use any looping constructs (for, while, do-while, ...). ► Be directly (not indirectly) recursive. ► Not create any new nodes, destroy any existing nodes or copy/replace the data item of any node. ► Not make temporary copies of the data involved using any other storage structures (arrays, stacks, queues, etc.). ► Use (if ever needed) no more than a small number of pointers to hold certain link addresses. ○ Not make temporary copies of the…
Linked list. Complete the function that takes as a parameter the head of a linked list and prints the linked list in reverse order. If the linked list had the contents: of,the,and,on,a,an,ok. Then the correct output would be: ok,an,a,on,and,the,of. Given: struct node { char word[31]; struct node *prev, next; }; void print_reverse(struct node *head) { }
Using C languge, implement programmer defined-data types with linked lists. A set of integers may be implemented using a linked list.Implement the following functions given the definition:typedef struct node* nodeptr;typedef struct node{int data;nodeptr next;}Node;typedef Node* Set;Set initialize();- simply initialize to NULLvoid display(Set s);- display on the screen all valid elements of the listSet add(Set s, elem);- simply store elem in the listint contains(Set s, int elem);- search the array elements for the value elemSet getUnion(Set result, Set s1, Set s2);- store in the set result the set resulting from the union of s1 and s2- x is an element of s1 union s2 if x is an element of s1 or x is an element of s2Set intersection(Set result, Set s1, Set s2);- store in the set result the set resulting from the intersection of s1 and s2- x is an element of s1 intersection s2 if x is an element of s1 and x is an element of s2Set difference(Set result, Set s1, Set s2);- store in the set…
def get_legal_word_scores(letters, dictionary, value_dict): """ Given a str of letters that we can use, and a dictionary that contains all legal words allowed in scrabble game, and a value_dict that maps each letter to a score, Returns a dictionary that contains all possible scores earned by any legal word as the key, and for each score, the score/key maps to a list of words that are from the dictionary made from the given letters and computes to that score. The list should be in alphabetical order. """
Write the following function that sorts and merges two lists into a new sorted list. The new list contains only even numbers. def myMergeEvenList(list1, list2): Enter list1: 10,5,6,7 Enter list2: 12,8,5,0,1 The merged list is: 0,6,8,10,12
Write a Python Code for the given function and conditions: Given function: def insert(self, newElement) Pre-condition: None. Post-condition: This method inserts newElement at the tail of the list. If an element with the same key as newElement already exists in the list, then it concludes the key already exists and does not insert the key.
Implements clone which duplicates a list. Pay attention, because if there are sublists, they must be duplicated as well. Understand the implementation of the following function, which recursively displays the ids of each node in a list Develop your solution as follows: First copy the nodes of the current list (self) Create a new list with the copied nodes Loop through the nodes of the new list checking the value field If this field is also a list (use isinstance as in the show_ids function) then it calls clone on that list and substitutes the value. Complete the code: def L4(*args,**kwargs): class L4_class(L): def clone(self): def clone_node(node): return <... YOUR CODE HERE ...> r = <... YOUR CODE HERE...> return r return L4_class(*args,**kwargs)
Please implement this function: void swap(int pos1, int pos2) {}. There's an answer from the previous teacher but he added '' node** hRef " in the function (see below) please correct without the href. For LinkedList, to maintain integrity of data in the structure, you are not to swap directly the element, nor remove a node. Instead, you are to only change the nodes' next pointers. PLEASE CORRECT THIS ONE void swap(node** hRef, int pos1, int pos2) { if (pos1 == pos2) return; node *prevNode1 = NULL; node* currNode1 = *hRef; while (currNode1 && currNode1->index != pos1) { prevNode1 = currNode1; currNode1 = currNode1->next; } node *prevNode2 = NULL; node *currNode2 = *hRef; while (currNode2 && currNode2->index != pos2) { prevNode2 = currNode2; currNode2 = currNode2->next; } if (currNode1 == NULL || currNode2 == NULL) return; if (prevNode1 != NULL) prevNode1->next =…
(IntelliJ) Write an easier version of a linked list with only a couple of the normal linked list functions and the ability to generate and utilize a list of ints. The data type of the connection to the following node can be just Node, and the data element can be just an int. You will need a reference (Java) or either a reference or a pointer (C++) to the first node, as well as one to the last node. * Create a method or function that accepts an integer, constructs a node with that integer as its data value, and then includes the node to the end of the list. If the new node is the first one, this function will also need to update the reference to the first node. This function will need to update the reference to the final node. Consider how to insert the new node following the previous last node, and keep in mind that the next reference for the list's last node should be null. * Create a different method or function that iteratively explores the list, printing the int data values as…
Write appropriate comments for the following partial code. Mention, the relation of linked list with the partial code.Partial Code: typedef struct node_s { char current[3]; int volts; struct node_s *linkp; } node_t;
What is the functionality of the following piece of code? public int function(){Node temp = tail.getPrev();tail.setPrev(temp.getPrev());temp.getPrev().setNext(tail);size--;return temp.getItem();}a) Return the element at the tail of the list but do not remove itb) Return the element at the tail of the list and remove it from the listc) Return the last but one element from the list but do not remove itd) Return the last but one element at the tail of the list and remove it from the list