Possibly useful information: The specific heat of (liquid) water is cw = 4186 J/(kg C° ). The heat of fusion for ice or water is L = 3.33 x 105 J/kg The latent heat of vaporization for water is 22.57 x 105 J/kg 1 calorie = 4. 186 Joules T (Kelvin) = T (Celsius) + 273 1. A 0.040 kg ice cube at 0 Celcius is placed in an insulated box that contains 0.007kg of steam at 100 Celsius. What is the equilibrium temperature reached by the closed system. NOTE: All of the ice melts.
Possibly useful information: The specific heat of (liquid) water is cw = 4186 J/(kg C° ). The heat of fusion for ice or water is L = 3.33 x 105 J/kg The latent heat of vaporization for water is 22.57 x 105 J/kg 1 calorie = 4. 186 Joules T (Kelvin) = T (Celsius) + 273 1. A 0.040 kg ice cube at 0 Celcius is placed in an insulated box that contains 0.007kg of steam at 100 Celsius. What is the equilibrium temperature reached by the closed system. NOTE: All of the ice melts.
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter21: Heat And The First Law Of Thermodynamics
Section: Chapter Questions
Problem 21PQ
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