potential difference

College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter19: Electric Potential And Electric Field
Section: Chapter Questions
Problem 15PE: The electric field strength between two parallel conducting plates separated by 4.00 cm is 7.50 104...
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A 4.96 g bead carries a charge of 17.2 µC. The bead is accelerated from rest
through a potential difference V, and afterward the bead is moving at 1.77 m/s.
What is the magnitude of the potential difference V?
Transcribed Image Text:A 4.96 g bead carries a charge of 17.2 µC. The bead is accelerated from rest through a potential difference V, and afterward the bead is moving at 1.77 m/s. What is the magnitude of the potential difference V?
Expert Solution
Step 1

Given:

Mass of bead is m=4.96 g

Charge is q=17.2 μC

The bead is accelerated from rest through V potential difference.

Velocity of bead is v=1.77 m/s

Note:

1 C=106 μC

1 N=1 kg·m/s2

1 J=1 Nm

1 J/C=1 V

Find:

Magnitude of potential difference.

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