Practice question: Find f(3) if 12 fx) = x2 . 2: Solution: To evaluate f(3), we simply plug in the value of 3 for x in the expression: f17) = 32 .2 = 7. Find f'(3) f'(3) represents the taking the first derivative of the expression and evaluating at x = 3: f'(x) = (2)3 (2-1) = (2)3 f'(3) = (2)3 = 6 Question: Find f(7) if f(x) = x2 + 7: f(7) = find f'(7) f'(7) =

Managerial Economics: Applications, Strategies and Tactics (MindTap Course List)
14th Edition
ISBN:9781305506381
Author:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris
Publisher:James R. McGuigan, R. Charles Moyer, Frederick H.deB. Harris
Chapter5: Business And Economic Forecasting
Section: Chapter Questions
Problem 1.4CE
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Practice question: Find f(3) if
12
f(x) = x2 - 2:
Solution: To evaluate f(3), we simply plug in the value of 3 for x in the expression:
f(7) = 32.2 = 7.
Find f(3)
f'(3) represents the taking the first derivative of the expression and evaluating at x = 3:
f'(x) = (2)3 (2-1) = (2)3
f'(3) = (2)3 = 6
Question: Find f(7) if
f(x) = x2 + 7:
f(7) :
find f'(7)
f'(7) =
Transcribed Image Text:Practice question: Find f(3) if 12 f(x) = x2 - 2: Solution: To evaluate f(3), we simply plug in the value of 3 for x in the expression: f(7) = 32.2 = 7. Find f(3) f'(3) represents the taking the first derivative of the expression and evaluating at x = 3: f'(x) = (2)3 (2-1) = (2)3 f'(3) = (2)3 = 6 Question: Find f(7) if f(x) = x2 + 7: f(7) : find f'(7) f'(7) =
Practice question: Differentiate the following function:
13
y = 5x 3/2
Solution: Using the power rule,
dy/dx = y' = (3/2)(5x (3/2) - 1) = 15/10x 1/2 = 3/2x 1/2
Question: Differentiate the given function:
y= 2x4/3
Instruction: enter each response as a fraction (i.e., 1/2, 3/4, 5/8, .)
dy/dx
= X
Transcribed Image Text:Practice question: Differentiate the following function: 13 y = 5x 3/2 Solution: Using the power rule, dy/dx = y' = (3/2)(5x (3/2) - 1) = 15/10x 1/2 = 3/2x 1/2 Question: Differentiate the given function: y= 2x4/3 Instruction: enter each response as a fraction (i.e., 1/2, 3/4, 5/8, .) dy/dx = X
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