predict the final temperature of an object (in celsius) if the object is 236.36 g, has a specific heat capacity of 0.180 J/g*C, lost 2344.37 J of heat to the surroundings, and had an initial temp of 19.15 celsius.

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 129.0 mg sample…

A: Mass of sample = m = 129 mg = 0.129 g Initial temperature = T1 = - 9.6°C Final temperature = T2 =…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 194.0 g sample…

A: Mass of sample = 194 gram Initial temperature = - 8.3℃ Final Temperature , T2 = 4.5 ℃ Change in…

Q: A chemist carefully measures the amount of heat needed raise the temperature of a 488.0 g sample of…

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Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 1.97 kg sample…

A: We know that heat involved and specific heat capacity of a system are related by the equation- ∆H =…

Q: When 151.0 mL of water at 26.0 C is mixed with 71.0 mL of water at 85.0 C, what is the final…

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Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 0.46 kg sample…

A: The solution is provided below;

Q: Since the water absorbs 127 J of heat, this means the unknown metal released 127 J of heat. Based on…

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Q: 86. When 2.8 J of heat are added to 5.6 g of an unknown metal, its temperature rises by 3.9 °C. Are…

A: The heat added to a system 'Q' to raise the temperature is determined using following formula: Q=m×…

Q: If it takes 41.72 joules to heat a piece of gold weighing 18.69g from 10.0°C to 27.0°C, what is the…

A: Given, the amount of heat taken by gold q = 41.72 joules amount of gold m = 18.69 g and increase in…

Q: If 4.0 grams of water at 1ºc absorbs 33 joules of heat, what will be the change in temperature of…

A: Given,Mass of water= 4gTemperature = 1 degree Celsius.Heat = 33J

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 267.0 g sample…

A: Mass of substance = m = 267.0 g Change in Temperature( ΔT)  = 7.3 - (-5.2) = 12.5 °C = 285.5 K Heat…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 320.0 mg sample…

A: Consider the given information is as follows; Heat needed (q) = +3.51 JMass of the sample = 320.0 mg…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 221.0g sample…

A: Specific heat capacity: The amount of heat required to increase the temperature of one gram of a…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 273.0 g sample…

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Q: 1-  During a chemical reaction, which of the following statements is ALWAYS true?  I) A system…

A: “Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: A 55-gram aluminum spoon (specific heat 0.88 J/g°C) at 54°C is placed in 150 mL of coffee at 105°C…

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Q: A sample of iron absorbs 62.3 J of heat, upon which the temperature of the sample increases from…

A: The amount of heat required is related to specific heat capacity as,…

Q: In order to change the temperature of 147 g of lead from 22 o C to 55.oC, how many Joules are…

A: Q = mc∆T Q = heat M = mass C = specific heat capacity ∆T = change in Temp.   M = 147 g ∆T = Tfinal –…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 212.0 g sample…

A: • The values provided in the question are:-  i) Mass of a substance, m = 212.0 g  ii) Initial…

Q: The specific heat of a certain type of metal is 0.128 J/(g*c). What is the final tempature if 305J…

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Q: Find the final temperature of water given an initial temperature of 28 ˚ C, a mass of 8 g, heat (q)…

A: Initial temperature of water (T1) = 28°C Mass of water (m) = 8 g Heat absorbed (q) = 184 J Specific…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 270.0 g sample…

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Q: When 435 J of heat is added to 3.4 g of olive oil at 21°C, the temperature increases to 85°C. What…

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Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 1.82 kg sample…

A: Answer: Whenever a substance absorbs the heat, its temperature rises but the magnitude of that…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 0.99 kg sample…

A: Given-> Weight of sample = 0.99 Kg = 0.99×1000 gm…

Q: how many joules of energy are released when 100.0 g of water cools from 98 degrees Celsius to 30° c…

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Q: An iron can weighing 50 grams absorbs 256.0 J of heat and warms by 11.4C. What is the specific heat…

A: The amount of heat required to raise the temperature of a substance by one degree Celsius is called…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 0.29 kg sample…

A: 0.45 or 4.49 * 10-1 J/g K

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 1.21 kg sample…

A: Please find your solution below : Calorimetry is a process which is used to measure the amount of…

Q: 3) Calculate the heat capacity of a piece of wood if 1500.0 g of the wood absorbs 6.75x104 joules of…

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Q: A 55.0g sample of metal z requires 675j of energy to heat it from 25.0 to 118.0 Celsius? Calculate…

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Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 682.0 mg sample…

A: • The values provided in the question are:-       i) Mass of a substance, m = 682.0 mg = 0.6820 g {…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 228.0 mg sample…

A: The formula to calculate heat is as follows: Q= ms∆T Q is heat released/absorbed. m is mass of the…

Q: If 801 J of heat is available, what is the mass in grams of iron (specific heat = 0.450 J/g･°C) that…

A: Given data : Heat (q) = 801 J Specific heat (C) = 0.450 J/g.°C Initial temperature (Ti) = 22.5 °C…

Q: A sample of a metal weighing 18.3 g was heated to 99.9°C, then placed into a calorimeter containing…

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Q: In the laboratory a student uses a "coffee cup" calorimeter to determine the specific heat of a…

A: Here, we need to calculate the value of specific heat of tin. Specific heat formula is used to…

Q: Given a 49.8-g49.8-g sample of this substance with a specific heat of 59.0 J/(kg·°C),59.0 J/(kg·°C),…

A: A sample whose temperature is changed from 180°C to 256°C, whose quantity of heat energy released is…

Q: The temperature of a 16.2g sample of gold increases from 20.5°C to 30°C. If the specific heat of…

A: Specific heat capacity is the amount of heat that is required to rise a temperature of 1 kg…

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 339.0 g sample…

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Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 744.0 mg sample…

A: mass = 744mg = 0.744g Initial Temperature = -7.8oC Final Temeprature = 12.8oC Heat = 3.60J

Q: If it takes 41.72 joules of heat for a piece of gold weighing 18.69 grams from 10.0oC to 27.0oC,…

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Q: In the laboratory a student determines the specific heat of a metal. He heats 18.4 grams of…

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Q: The ΔE of a system that absorbs 184 J of heat from the surroundings and has 42 J of work done on the…

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Q: Calculate the specific heat capacity of a piece of wood if 1500.0 g of the wood absorbs 67,500…

A: Specific heat capacity can be calculated as follows

Q: How much heat is required to raise the temperature of 15 x 10g of water from 45F to 130F? The…

A: Answer: This question is based on the following formula: Q=mS∆There:Q=heat exchangedm=mass of the…

Q: 6. If it takes 44.72 joules to heat a piece of metal weighing 16.89 g from 10.0°C to 29.0°C, what is…

A: q = 44.72 J  m = 16.89 g  Ti = 10.0°C  Tf = 29.0°C  c = ?

Q: A gas does 135 J of work while expanding, and at the same time it absorbs 156 J of heat. What is the…

A: Thermodynamics is the study of heat in motion.

Q: A chemist carefully measures the amount of heat needed to raise the temperature of a 799.0 mg sample…

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Q: An object that has a mass of 75 g is heated from 50°C to 93°C. If it takes 3000 J for the…

A: Given: Mass of object = 75 g Initial temperature = 50°C Final temperature = 93°C Heat required =…