Predict the output of the following program: #include int main(int argc, const char * argv[]) { int a[] = {1, 2, 3, 4, 5, 6}; std::cout << (1 + 3)[a] - a[0] + (a + 1)[2]; }
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Predict the output of the following program:
#include <iostream>
int main(int argc, const char * argv[])
{
int a[] = {1, 2, 3, 4, 5, 6};
std::cout << (1 + 3)[a] - a[0] + (a + 1)[2];
}
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- Need help converting this C++ code to java. 1. Bubble Sort #include <bits/stdc++.h> using namespace std; void swap(int * xp, int * yp) { int temp = * xp; * xp = * yp * yp - temp;} void bubbleSort(int arr[], int n) { int i, j; for (i = 0; i < n - 1; i++) for (j - 0; j < n - i - 1; j++) if (arr[j] > arr[j + 1]) swap( & arr[j], & arr[j + 1]);}void printArray(int arr[], int size) { int i; for (i = 0; i < size; i++) cout << arr[i] << " "; cout << end1;} //Driver ClassLoaderint main(){ int arr[] = {1, 2, 3, 7, 5, 6, 4}; int n = sizeof(arr)/sizeof(arr[0]); bubbleSort(arr, n); cout <<"Sorted Array: \n"; printArray(arr, n); return 0;} 2. Inserted Sort #include <bits/stdc++.h>using namespace std;void insertionSort(int arr[], int n){ int i, key, j; { key = arr[i]; j = i-1; while (j >= 0 && arr[j]>key) { arr[j+1]=arr[j]; j=j-1;…Please Help In JAVA Here is the skeleton of a code for insertion sorting in a functional language. You have to add right lines of codes for the language you choose (C, C++, C#, JAVA etc,). The following sample is for C++ (define (insert L M) (if (null? L) M (if (null? M) L (if (< (car L) (car M)) (cons (car L) (insert (cdr L) M)) (cons (car M) (insert (cdr M) L)))))) ;; Exp. (insertionsort '(4 2 10 3 -1 5)) ==> (-1 2 3 4 5 10)(define (insertionsort L) (if (null? L) '() (insert (list (car L)) (insertionsort (cdr L))))) (define (random-list n) (unless (exact-nonnegative-integer? n) (raise-argument-error 'make-list "exact-nonnegative-integer?" 0 n)) (let loop ([n n] [r '()]) (if (zero? n) r (loop (sub1 n) (cons (random 2147483647) r))))) Sample function call:(insertionsort (random-list 10000)) Hint: most languages have some function to determine the runtime of functionsQ#1 Write a recursive function printRev ( int a[ ], int s, int e) that receives an integer array a [ ], a start index s, and an end index e. The function should print the array elements in reverse order. void printRev ( int a[ ], int s, int e); Trace your function given the following array and function call. Draw your steps. int a[ ] = {4, 2, 3, 5};and printRev(a, 0, 3); language c++
- Write a C function arrDivN() that takes one array of integers and three integer numbers (say ar, n1, n2, n3) as parameters, it stores into the array the numbers divisible by n3 between n1 and n2 (both inclusive) and returns the count of the numbers stored in the array. Prototype: int arrDivN(int ar[], int n1, int n2, int n3);make table for this codding #include <cmath> #include <iostream> using namespace std; //declaration of function void Smallest(int n, int arr[]); void Largest(int n, int arr[]); void findMean(int a[], int n); void standardDeviation(int a[], int n); //main coding int main() { int a[100]; int n; cout<<"Input number of elements in the array "; cin>>n; int i; for (i=0;i<n;i++) { cout<<"Insert data : "; cin>> a[i]; } Smallest(n,a); Largest(n,a); findMean(a,n); standardDeviation(a,n); return 0; } //Function: Smallest //It will take a int n and int arr[] //and find the smallest value with the frequency void Smallest(int n, int arr[]) { int mn = arr[0], freq = 1; for (int i = 1; i < n; i++) { if (arr[i] < mn) { mn = arr[i]; freq = 1; } else if (arr[i] == mn) freq++; } cout<<endl<<"Smallest value is "<<mn<<" and it's frequency is "<<freq<<endl; } //Function: Largest //It will take a int n and…Modified Recursive Binary Search • Write C++ program hw7.cpp that meets the following requirements: – First, write a recursive binary search function with the following prototype: int binarySearch(int array[], int first, int last, int value); – Now suppose we have a sorted array like this: int a[SIZE] = { 3, 5, 7, 9, 22, 22, 22, 22, 30, 35, 51, 52, 73 }; – Then the following statement int index = binarySearch(a, 0, SIZE-1, 22); – would return one of the indices that match the target value (22), and it could be index 4, 5, 6, or 7. – Now, your mission is to modify this recursive binary search function to always return the leftmost index when there are multiple indices that match the target value. Thus, in the above case, the function must return index 4. – If no match found, the function returns -1. – Write a main function that checks if your modified binary search function works as expected with at least 3 example arrays. – Note: your modified binary search function must ensure the…
- Write a lambda expression to count odd numbers in the following array, using a seed value of 0. Display your result on Console. int[] array = { 8,2,2,24,5,7,5,3,2,10};Write a C function countEven() that takes an integer array and the number of elements in the array as parameters, finds and returns the number of even numbers in the array. Prototype: int countEven(int ar[], int n);in c++ 1. Write a function that takes a 1 Dimensional array and an integer n andreturns the number of times ‘n’ appears in the array. If ‘n’ does not appearin the array, return -1.2. Write a function that takes a 2 Dimensional array and returns the positionof the first row with an odd sum. Assume that the column size is fixed at 4.If no sum is odd, return -13. Write a class, “pie”, that has a number of slices (int slices) as a privateproperty. Construct the pie with a number of slices and remove a slice witha function. Tell the user how many slices are in the pie.
- In C++ The function below, zeroesToFives takes an array of integers and changes any zeroes in the array to fives and returns the count of array elements that were updated. Write at least ten test cases using assertions for zeroesToFives. You should test at least three boundary/edge cases.def find_root4(x, epsilon): ''' IN PYTHON Assume: x, epsilon are floating point numbers and epsilon > 0 Use bisection search to find the following root of x such that If x >=0, return y such that x - epsilon <= y ** 2 <= x + epsilon Else, return y such that x - epsilon <= y ** 7 <= x + epsilon Note: You must use bisection search to implement the function. ''' pass#include<stdio.h> #include<iostream>using namespace std; int main() { int arr [7] = {9, 4, 1, 6, 2}; int i, j, k, temp, n=5; for(i=0;i<n-1;i++){ for (j = i+1; j<n; j++){ if (arr[i]>arr[j]){ //swap the elements temp = arr[i]; arr[i] = arr[j]; arr[j] = temp; } } } cout<<"The sorted array is: "; for (k=0; k<n;k++) { cout<<arr[k]<<' '; } } Question: Rewrite the Program using function.