(3) There is a function void fnE(int i, int num) that runs in 1000-i steps, regardless of what num is. Consider the following code snippet: void fnA(int S[]) { int n = s.length; for (int i=0;i

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter6: User-defined Functions
Section: Chapter Questions
Problem 38SA
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(3) There is a function void fnE(int i, int num) that runs in 1000-i steps, regardless of what
num is. Consider the following code snippet:
void fnA(int S[]) {
S.length;
for (int i=0;i<n;i++) {
fnE(i, S[i]);
int n =
}
}
What's the running time in Big-O of fnA as a function of n, which is the length of the array S. You
should assume that it takes constant time to determine the length of an array.
(4) Show that h(n) = 16n2 + 1ln* +0.1n³ is not O(n“).
Transcribed Image Text:(3) There is a function void fnE(int i, int num) that runs in 1000-i steps, regardless of what num is. Consider the following code snippet: void fnA(int S[]) { S.length; for (int i=0;i<n;i++) { fnE(i, S[i]); int n = } } What's the running time in Big-O of fnA as a function of n, which is the length of the array S. You should assume that it takes constant time to determine the length of an array. (4) Show that h(n) = 16n2 + 1ln* +0.1n³ is not O(n“).
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