Problem 02: For the following series-parallel network, the supply voltage E 300VZ60° as shown in Figure02:X1 XcIR2Here,R3R4Ri -7.5 Ω; Χ -2.5Ω; Χcι -5ΩR2 = 10 2; X12 = 20 2R3 = 10 Q; Xc2= 5 2R4 = 10 2; XL3 = 40 Q; Xc3 = 20 2EX13X12Figure 02(e) The branch current (in both polar and Cartesian forms):

Answered: Image /qna-images/answer/3c749ccf-0ea4-4680-b3bc-1a5203d1dd55.jpg

Problem 02: For the following series-parallel network, the supply voltage E 300VZ60° as shown in Figure 02: X1 XcI Here, + R2 R3 R4 Ri -7.5 Ω; Χ -2.5Ω; Χcι -5Ω E R2 = 10 2; X12 = 20 2 X13 R3 = 10 Q; Xc2 = 5 2 R4 = 10 Q; XL3 = 40 Q; Xc3 = 20 2 Figure 02 (e) The branch current (in both polar and Cartesian forms):

Problem 02: For the following series-parallel network, the supply voltage E 300VZ60° as shown in Figure 02: X1 XcI Here, + R2 R3 R4 Ri -7.5 Ω; Χ -2.5Ω; Χcι -5Ω E R2 = 10 2; X12 = 20 2 X13 R3 = 10 Q; Xc2 = 5 2 R4 = 10 Q; XL3 = 40 Q; Xc3 = 20 2 Figure 02 (e) The branch current (in both polar and Cartesian forms):

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter6: Power Flows

Section: Chapter Questions

Problem 6.61P

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