Problem 1In order to maximize the yield of a certain process, an engineer studied the impact offive factors 1, 2, 3, 4 and 5 on yield using the following experimental design.1+I2 3++ ++I+I++++ + +4 5+I++++I++ +(a) Denoting the above design as a 2k-p design, what are k and p?(b) Write a set of defining relations for this design.(c) What is the resolution of this design ?(d) Which effects are clear?(e) Write down the word length pattern of the design.(f) How many points shall figure in the half-normal plot? Which factorial effects wouldthey represent ? Clearly explain your answer.

Given information: 1 2 3 4 5 - - - + - + - - - + - + - - + + + - + - - - + - - + - +…

Answered: Problem 1 In order to maximize the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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In Problem 3 in Chapter 3, we estimated the equationsleep = 3,638.25 - .148 totwrk -11.13 educ + 2.20 age (112.28) (.017) (5.88) (1.45)n= 706, R^2 = 0 .113,where we now report standard errors along with the estimates.(i) Is either educ or age individually significant at the 5% level against a two-sided alternative? Show your work.(ii) Dropping educ and age from the equation givessleep = 3,586.38 - 0.151 totwrk (38.91) (.017)n= 706, R^2= 0.103. Are educ and age jointly significant in the original equation at the 5% level? Justify your answer.(iii) Does including educ and age in the model greatly affect the estimated tradeoff between sleeping and working? Note: the attached image is the problem 3 in Chapter 3 mentioned in the above question. You may have to refer to it.
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PROBLEM 3: Quiz scores L n = 13 students 5 7 9 10 8 9 0 6 7 10 9 10 8 example of how it needs to be answered: PROBLEM: #colds / year n=18 subjects 10; 8; 5; 2; 3; 3; 3; 6; 4; 2; 4; 5; 4; 4; 1; 0; 3; 5; For computations done by hand, data must be ordered. 0 1 2 2 3 3 3 3 4 Median 4 4 4 5 5 5 6 8 10 Q1 Q3 Sample mean = =72/18 = 4 colds Sample median = 4 colds (midpoint of data) Sample mode = 3 and 4 (the value that occurs most often; this is a bimodal data set) First Quartile (approximation) = 0.25 * N = 0.25 * 18 = 4.5; If the value is not an integer, we can round it up to the nearest integer 5 à value is 3 Third Quartile (approximation) = 0.75 * N = 0.75 * 18 = 13.5 à 14 à value is 5 Range = max – min =10 – 0 = 10 IQR = Q3 – Q1 = 5 – 3 = 2…
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