Problem 1. Let 4 0 0 0. -1 2 0 -1 5 2 6. 13 1 5 2 ,D = 3 A = 1 0. ,E = 1 3 1 6. 0 7 -3 0 2 4 1 3 10 2 4 1 (e) det(D) (f) det(D"(4E")– 4(ED)") | (g) det(B-1)

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