Problem 2: A hollow cylinder, closed at both ends, is situated in an electric field given by 24 Ē(x) = Eo -()*++) (二) The cylinder, with length L and radius R, is centered at the origin with it's symmetry axis on the x axis. Refer to the figure. L R Part (a) Integrate to find an expression for the total electric flux through the cylinder in terms of defined quantities and enter the expression. =(E₁R² L³)/(16 x₁5) ✓ Correct! $ Part (b) For L = 5.29 m, R = 0.285 m, E₁ = 6.33 V/m, and xo +--377.54 g=-377.5 V.mx Attempts Remain = 1.00 m, find the value, in volt meters, of the electric flux through the cylinder. Part (c) If the electric field changes to, 2 E(x) = E 323 (#) +423 +4154 enter an expression for the total electric flux in terms of defined quantities. X

Physics for Scientists and Engineers: Foundations and Connections
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Chapter25: Gauss’s Law
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Problem 2: A hollow cylinder, closed at both ends, is situated in an electric field given by
24
Ē(x) = Eo
-()*++)
(二)
The cylinder, with length L and radius R, is centered at the origin with it's symmetry axis on the x axis.
Refer to the figure.
L
R
Part (a) Integrate to find an expression for the total electric flux through the cylinder in terms of defined quantities and enter the expression.
=(E₁R² L³)/(16 x₁5) ✓ Correct!
$ Part (b) For L = 5.29 m, R = 0.285 m, E₁ = 6.33 V/m, and xo
+--377.54
g=-377.5 V.mx Attempts Remain
=
1.00 m, find the value, in volt meters, of the electric flux through the cylinder.
Part (c) If the electric field changes to,
2
E(x) = E 323
(#)
+423 +4154
enter an expression for the total electric flux in terms of defined quantities.
X
Transcribed Image Text:Problem 2: A hollow cylinder, closed at both ends, is situated in an electric field given by 24 Ē(x) = Eo -()*++) (二) The cylinder, with length L and radius R, is centered at the origin with it's symmetry axis on the x axis. Refer to the figure. L R Part (a) Integrate to find an expression for the total electric flux through the cylinder in terms of defined quantities and enter the expression. =(E₁R² L³)/(16 x₁5) ✓ Correct! $ Part (b) For L = 5.29 m, R = 0.285 m, E₁ = 6.33 V/m, and xo +--377.54 g=-377.5 V.mx Attempts Remain = 1.00 m, find the value, in volt meters, of the electric flux through the cylinder. Part (c) If the electric field changes to, 2 E(x) = E 323 (#) +423 +4154 enter an expression for the total electric flux in terms of defined quantities. X
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