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Problem 2: The footing shown on the next carries a 40cm '40cm column. For the soil profile shown check the safety against: a) Bearing capacity failure b) Total settlement failure 400 kN c) Tilting failure The soils have the following properties: 1 m 2mx2m Sand 1: c = 25 kPa, o = 15° y = 17.5 kN/m3. E, = 25 MPa H = 0.35 Sand 1 1 m

Problem 2: The footing shown on the next carries a 40cm '40cm column. For the soil profile shown check the safety against: a) Bearing capacity failure b) Total settlement failure 400 kN c) Tilting failure The soils have the following properties: 1 m 2mx2m Sand 1: c = 25 kPa, o = 15° y = 17.5 kN/m3. E, = 25 MPa H = 0.35 Sand 1 1 m

Principles of Foundation Engineering (MindTap Course List)
Principles of Foundation Engineering (MindTap Course List)
9th Edition
ISBN:9781337705028
Author:Braja M. Das, Nagaratnam Sivakugan
Publisher:Braja M. Das, Nagaratnam Sivakugan
Chapter7: Ultimate Bearing Capacity Of Shallow Foundations: Special Cases
Section: Chapter Questions
Problem 7.16P
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Problem 2: The footing shown on the next carries a 40cm '40cm column. For the soil profile shown check the safety against: a) Bearing capacity failure b) Total settlement failure 400 kN c) Tilting failure The soils have the following properties: 1 m 2mx2m Sand 1: c = 25 kPa, o = 15° y = 17.5 kN/m3, E, = 25 MPa H = 0.35 Sand 1 1 m Clay 1: c = 65 kPa, = 0° Ysat = 19.8 kN/m3. Es = 10 MPa µ = 0.30, Cc = 0.15, C, = 0.05 Pc = 40 kPa, eo = 1.0 Clay 1 1 m Clay 2: c = 95 kPa, = 0° Ysat = 20.8 kN/m. Es = 20 MPa u = 0.30, C = 0.25, C, = 0.10 P = 150 kPa, e, = 0.4 Clay 2 1 m Sand 2 Rock is very deep
Transcribed Image Text:Problem 2: The footing shown on the next carries a 40cm '40cm column. For the soil profile shown check the safety against: a) Bearing capacity failure b) Total settlement failure 400 kN c) Tilting failure The soils have the following properties: 1 m 2mx2m Sand 1: c = 25 kPa, o = 15° y = 17.5 kN/m3, E, = 25 MPa H = 0.35 Sand 1 1 m Clay 1: c = 65 kPa, = 0° Ysat = 19.8 kN/m3. Es = 10 MPa µ = 0.30, Cc = 0.15, C, = 0.05 Pc = 40 kPa, eo = 1.0 Clay 1 1 m Clay 2: c = 95 kPa, = 0° Ysat = 20.8 kN/m. Es = 20 MPa u = 0.30, C = 0.25, C, = 0.10 P = 150 kPa, e, = 0.4 Clay 2 1 m Sand 2 Rock is very deep
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