Problem 2. Given the following reaction, determine the AH°F (in kJ/mol) of SiCl4(g): SiO2(s) + HCI(g) >+ H20(g) AH°rxn = 139.5 kJSiO2(s)Sicl4(g)%3DAH°FHC(g)SiCl4(g)H2O(g)(kJ/mol)-910.9-92.3?-241.8

Thermodynamics is the branch of chemistry that mainly deals with the heat transfer between system…

Problem 2. Given the following reaction, determine the AH°F (in kJ/mol) of SiCl4(g): SiO2(s) + HClg) → Sicl4(g) + H20(g) AH°rxn = 139.5 kJ AH°F SiO2(s) HClg) SiCl4(g) H2O(g) (kJ/mol) -92.3 -241.8 -910.9

Problem 2. Given the following reaction, determine the AH°F (in kJ/mol) of SiCl4(g): SiO2(s) + HClg) → Sicl4(g) + H20(g) AH°rxn = 139.5 kJ AH°F SiO2(s) HClg) SiCl4(g) H2O(g) (kJ/mol) -92.3 -241.8 -910.9

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter2: Polar Covalent Bonds; Acids And Bases

Section2.9: Predicting Acid–base Reactions From Pka Values

Problem 14P

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Question

Problem 2. Given the following reaction, determine the AH°F (in kJ/mol) of SiCl4(g): SiO2(s) + HCI(g) >
+ H20(g) AH°rxn = 139.5 kJ
SiO2(s)
Sicl4(g)
%3D
AH°F
HC(g)
SiCl4(g)
H2O(g)
(kJ/mol)
-910.9
-92.3
?
-241.8

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Problem 2. Using the enthalpy of reaction. The next six questions are part of problem 2. Please refer back to this problem statement if you need to refresh your memory. How much did our sodium-in-water demonstration raise the temperature of water in the dessicator jar? The reaction we performed was: Na(s) + H2O(l) →→ NaOH(aq) + 1/2H2(g) qreaction = ΔΔrHo = -184 kJ/mol-rxn Assuming the dessicator jar is well insulated (like our coffee-cup calorimeter), the energy balance is: 0 = qsystem = qreaction + qwater ⇒⇒ qreaction = -qwater qreaction = -mwater*Cwater*ΔΔTwater The data from the demonstration was: (a) 1.0 kg water, (b) 22.0oC, (d) Cwater = 4.18 J/g-K, (e) mNa = 0.21 g What is the molar mass of sodium, Na, in g/mol? How many moles of sodium were added to the water (in moles)? What was the change in energy, in joules, when the reaction occurred with the given amounts? What was the mass of…
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