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2. AClsle) → ACI3(e) + Clz{e) AH = ? Given: Aa(s) + 6CI2(e) → 4ACI3{g) AH = -2439 kJ 4ACIS(e) → A4(s) + 10Cl2le) AH = 3438 kJ

2. AClsle) → ACI3(e) + Clz{e) AH = ? Given: Aa(s) + 6CI2(e) → 4ACI3{g) AH = -2439 kJ 4ACIS(e) → A4(s) + 10Cl2le) AH = 3438 kJ

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 53QAP: How many kJ are equal to 3.27 L atm of work?
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Instruction: Find the following ΔH for the reaction below.

ACl5(g) → ACl3(g) + Cl2(g)               ΔH = ?


Given:
A4(s) + 6Cl2(g) → 4ACl3(g)                ΔH = -2439 kJ
4ACl5(g) → A4(s) + 10Cl2(g)              ΔH = 3438 kJ

2. AClsle) → ACI3(e) + Clz{e) AH = ? Given: Aa(s) + 6CI2(e) → 4ACI3{g) AH = -2439 kJ 4ACIS(e) → A4(s) + 10Cl2le) AH = 3438 kJ
Transcribed Image Text:2. AClsle) → ACI3(e) + Clz{e) AH = ? Given: Aa(s) + 6CI2(e) → 4ACI3{g) AH = -2439 kJ 4ACIS(e) → A4(s) + 10Cl2le) AH = 3438 kJ
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