Problem 2. Three forces are applied to a disk of radius 0.35 m and mass 2.5 kg, as shown in figure below. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. The moment of inertia of a disk about its center is I = (1/2)MR². (a) What is the net torque on the disk due to these three forces for an axis perpendicular to the disk and passing through its center? (b) What is the angular acceleration of the disk? 11.9 N 0.350 m 40.0 14.6 N 8.50 N

Physics for Scientists and Engineers: Foundations and Connections
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Chapter13: Rotation Ii: A Conservation Approach
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Problem 7PQ: A 12.0-kg solid sphere of radius 1.50 m is being rotated by applying a constant tangential force of...
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Problem 2. Three forces are applied to a disk of radius 0.35 m and mass 2.5 kg, as shown in figure
below. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle
with the radius. The moment of inertia of a disk about its center is I = (1/2)MR².
(a) What is the net torque on the disk due to these three forces for an axis perpendicular to the disk and
passing through its center?
(b) What is the angular acceleration of the disk?
11.9 N
0.350 m
40.0° 14.6 N
8.50 N
Transcribed Image Text:Problem 2. Three forces are applied to a disk of radius 0.35 m and mass 2.5 kg, as shown in figure below. One force is perpendicular to the rim, one is tangent to it, and the other one makes a 40.0° angle with the radius. The moment of inertia of a disk about its center is I = (1/2)MR². (a) What is the net torque on the disk due to these three forces for an axis perpendicular to the disk and passing through its center? (b) What is the angular acceleration of the disk? 11.9 N 0.350 m 40.0° 14.6 N 8.50 N
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