Problem 3: Variable Live Load Placement 24'-0" + 28'-0" 24'-0" This beam supports a Dead Load and a Live Load. The Dead Load is uniform across all spans. The Live Load is a uniform load that varies so that it could be on some, all, or none of the spans. Draw the various live loading scenarios that will generate the maximum moments (positive and negative) in the critical regions of the beam. This is a qualitative problem, so no analysis is required. If you would like to run the analysis, assume a Dead Load of 1.64 kip/ft and a Live Load of 1.00 kip/ft.

Problem 3: Variable Live Load Placement 24'-0" + 28'-0" 24'-0" This beam supports a Dead Load and a Live Load. The Dead Load is uniform across all spans. The Live Load is a uniform load that varies so that it could be on some, all, or none of the spans. Draw the various live loading scenarios that will generate the maximum moments (positive and negative) in the critical regions of the beam. This is a qualitative problem, so no analysis is required. If you would like to run the analysis, assume a Dead Load of 1.64 kip/ft and a Live Load of 1.00 kip/ft.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The tower crane is used to hoist a 2-Mg load upwardat constant velocity. The 1.5-Mg jib BD and 0.5-Mg jib BChave centers of mass at G1 and G2, respectively. Determinethe required mass of the counterweight C so that the resultantmoment produced by the load and the weight of the towercrane jibs about point A is zero. The center of mass for thecounterweight is located at G3.
Civil - Axially loaded Reinforced concrete column Problem - Assuming = 4ksi and f_{y} = 60ksi find the nominal failure capacity of a 10in .*10 in. axi- ally loaded tied rectangular column with four No. 9 bars, as shown in Figure 7.12. Can this column support a live load of 100 kips and a dead load of 100kips?.
1. A simply supported 5 meter timber beam carries a 5kN/m uniformly distributed load. If the beam’s Ix is 260.4166 x 10^6 mm^4 and fb= 7.50 MPa, the maximum moment development is? a) 14.656 kN-m b) 15.625 kN-m c) 16.625 kN-m d) 17.625 kN-m 2. What is VMax for the beam of question 1? a) 10.5 kN b) 11.5 kN c) 12.5 kN d) 13.5 kN 3. What is the beam’s depth of question 1? a) 180 mm b) 200 mm c) 220 mm d) 250 mm
The tie rod is used to support this overhang at theentrance of a building. If it is pin connected to the buildingwall at A and to the center of the overhang B, determine ifthe force in the rod will increase, decrease, or remain thesame if (a) the support at A is moved to a lower position D,and (b) the support at B is moved to the outer position C.Explain your answer with an equilibrium analysis, using dimensions and loads. Assume the overhangis pin supportedfrom the building wall.
Two distributed loads act on the beam AB. If the resultant of this loads is a 2400 N-mcounterclockwise couple (a) Determine the load intensity, w at B and the distance “a” (b) what are thereactions at A and B ?
A short tied column carries an axial dead load of 1070 kN and live load of 981 kN. If fc' = 27.50 MPa, fy = 413.50 MPa. 1. Which of the following gives the probable size of the tied column. a. 400x400 b. 300x300 c. 500x500 d. 550x550 2. Which of the following gives the number of 28 mm diameter main reinforcing bars. a. 4 bars b. 8 bars c. 6 bars d. 10 bars 3. Which of the following gives the spacing of 10 mm tie wires. a. 300 mm b. 350 mm c. 400 mm d. 500 mm
Table of values: bf = 1482 mmbw 462 mmt = 292 mm fc' = 28.2 MPafy = 384 MPad = 1011 mmd' = 112 mmL(beam) = 15.1 mW_D1= 48.4 kN/mW_L1 = 56.9 kN/mW_D2 = 184.4 kN/mW_L2 = 208.9 kN/mPROBLEM: A simply-supported T-beam is subjected to two pairs of distributed loads: pair 1 (W_D1, W_L1)and pair 2 (W_D2, W_L2). The geometric, material and loading properties are all given on thetable above. 1. Solve for the height of the compression stress block using pair 1. 2. Solve for the theoretical steel area using pair 1. 3. Using Es = 0.004, solve for the theoretical steel area using pair 2. 4. Using Es = 0.005, solve for the theoretical steel area using pair 2.
Task 1a. Draw a moment diagram and determine the largest moment at support and field in the below statically indeterminatebeam.b. How much does the largest moment at support and beam change if the length of each bay (L) is increased from 1m to 2m?Assume the load q =10 kN/m . Tip: The task is to make diagrams for the given beam with 2L as total length. What to think about whenusing substitution (L′ = 2L) is to keep track of that variable all the time ultimately the substitutedthe variable is returned for a correct answer. If you make a substitution of the length (L′ = 2L) then it should be returned to the answer. Task 2A cylindrical pin made of carbon steel is loaded with a maximum possible twisting moment Mv. Maximum allowedshear stress is Tmax = 40 MPa. The pin has the diameter measurement d = 50 mm, and the length measurement L = 250 mm.Calculate the free end distortion θ in degrees. G=80 GPa.
Given: Mmax= 15.625 kN-m Vmax= 12.5 kN Depth of the beam= 250 mm 1. A simply supported 5 meter timber beam carries a 5 kN/m uniformly distributed load. If the beam's Ix is 260.4166 x 10^6 mm^4 and fb = 7.50 MPa, what is the base of the beam? a) 150 mm b) 180 mm c) 200 mm d) 220 mm 2. The shear stress fv developed for the beam of question 1 is a) 0.375 MPa b) 0.50 MPa c) 0.75 MPa d) 0.85 MPa
Two distributed loads act on the beam AB. If the resultant of this loads is a 2400 N-mcounterclockwise couple (a) Free Body Diagram (b) Determine the load intensity, w at B and the distance “a” (c) what are thereactions at A and B ?
Please Answer it fast on Sheet of paper. F1=1.5KN ,F2=3.8KN, a=3.6m ,b=2.0m ,c=1.3m. You need to find Forces in member (CH,AH and CD) And whether it's +ve or -ve.
For questions 2A and 2B, refer to the load and shear diagrams below. 2A. What is the slope of the shear diagram of the line from B to C?A.15 KN/mB.16 KN/mC.24.46 KNmD.11.26 KNmThe change in moment [KNm] of the diagram above from point A to the concentrated load is nearest toA.98B.99C.100D.101