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Problem 4: (Finding and using Taylor series) 1 to show that the Taylor series centered at a = 0 for А. Use the Taylor series centered at x = 0 for 272 is 2(k + 1)k+2. To earn full credit, you must work entirely in summation notation. (1 - x)2 k=0 (Problem 4, continued) 222 В. Use Taylor series to compute lim If the limit is oo or -0, make sure to indicate this. 20+ (1 – x)² sin(x²)' 2.a2 /(1 – x)² sin(a²) 2.x2 Hint: One way to proceed is to utilize the result from Part A by noting that as (1 – x)² sin(x²)

Problem 4: (Finding and using Taylor series) 1 to show that the Taylor series centered at a = 0 for А. Use the Taylor series centered at x = 0 for 272 is 2(k + 1)k+2. To earn full credit, you must work entirely in summation notation. (1 - x)2 k=0 (Problem 4, continued) 222 В. Use Taylor series to compute lim If the limit is oo or -0, make sure to indicate this. 20+ (1 – x)² sin(x²)' 2.a2 /(1 – x)² sin(a²) 2.x2 Hint: One way to proceed is to utilize the result from Part A by noting that as (1 – x)² sin(x²)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Problem 4: (Finding and using Taylor series) 1 to show that the Taylor series centered at x = 0 for A. Use the Taylor series centered at x = 0 for 1- x 2.x2 is > 2(k + 1)æ*+2. To earn full credit, you must work entirely in summation notation. (1 — х)2 k=0 (Problem 4, continued) 2x2 В. Use Taylor series to compute lim If the limit is ∞ or -∞, make sure to indicate this. x→0+ (1 – x)² sin(x²)* 2a² /(1 – x)² sin(x²) 2x2 Hint: One way to proceed is to utilize the result from Part A by noting that as (1 – x)² sin(x²)
Transcribed Image Text:Problem 4: (Finding and using Taylor series) 1 to show that the Taylor series centered at x = 0 for A. Use the Taylor series centered at x = 0 for 1- x 2.x2 is > 2(k + 1)æ*+2. To earn full credit, you must work entirely in summation notation. (1 — х)2 k=0 (Problem 4, continued) 2x2 В. Use Taylor series to compute lim If the limit is ∞ or -∞, make sure to indicate this. x→0+ (1 – x)² sin(x²)* 2a² /(1 – x)² sin(x²) 2x2 Hint: One way to proceed is to utilize the result from Part A by noting that as (1 – x)² sin(x²)
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