Problem 4 Hypothesis Testing for one continuous outcome The NCHS-reported mean total cholesterol level was 203 in 2002 for all adults 15 patients are enrolled in a 6-week study to test the efficacy of a new drug gne-tauled Lewertail Is the drug effective in the reduction of cholesterol compared to the historical At the end of 6 weeks: -n 15 - X 195.9 mean? Complete the five step hypothesis testing procedure. - s 28.7 JONES& BARTLETT LEARNING 2011 Jones & Bartlett Learning, LLC www.jbleaming.com Chart Your Own Course
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- Problem 10.6. Does the rate of voter turnout vary significantly by the type of election? A random sample of voting precincts displays the following pattern of voter turnout by election type. Assess the results for significance To know which groups are different from one another, we need to examine the results from the post hoc test analysis. Not all of what you get needs to be examined. Discuss final results using APA format. In addition to referring to information from the previous two tables,Question 6 In a study with a total of 200 people, you have determined that typists have an incidence of 25 per 100 (25%) of carpal tunnel syndrome compared to only 5 per 100 (5%) of people employed in professional, white-collar occupations. This was a 2-year follow-up study and there was no loss to follow-up. All subjects in the study were free from carpal tunnel syndrome at the beginning of the study. Use the following information to set up a 2 x 2 table and calculate appropriate measure of association. b) Draw the 2x2 table and complete the table.Question 3 A survey sponsored by The American Dietetic Association and the agribusiness giant ConAgra found that 53% of office workers take 30 minutes or less for lunch each day. Approximately 37% take 30 to 60 minutes, and 10% take more than an hour. What additional information you want to know before you accepted the results of the survey? 2. Discuss the four types of survey errors in the context of this survey
- Problem 3: A research team wants to investigate the usefulness of relaxation training for reducing levels of anxiety in individuals experiencing stress. They identify 30 people at random from a group of 100 who have “high stress” jobs. The 30 people are divided into two groups. One group acts as at the control group- they receive no training. The second group of 15 receive the relaxation training. The subjects in each group are then given an anxiety inventory. The summarized results appear below where higher scores indicate greater anxiety. Test the significant difference using alpha level @ 0.01 Control: 38 40 35 36 35 32 31 30 28 26 24 21 18 34 22 Relaxation: 35 32 30 34 30 32 28 27 22 22 18 17 17 25 21Question 1In each of the following situations, identify the population and the sample(i). There are 50 books in statistics in our library which contains a collection of 5,000 books.(ii). About 20% of the stones heaped on the building site are round in shape.(iii). The dream that there will be more female than male politicians in Ghana will never be realized(iv) About 10% of pregnant mothers reporting to hospitals are infected with HIV virus.(v) Since the last major earthquake in 1939, there have been 60 earth tremors in Ghana, with 20 these occurring over the past 5 years.question 28. I will submit this problem in three parts because it is long, and i was asked to seperate longer problems so you are not asked to do more than what you are being paid for. part 1 problem #28 Before the furniture store began its ad campaign, it averaged 146 customers per day. The manager is investigating if the average is larger since the ad came out. The data for the 16 randomly selected days since the ad campaign began is shown below: 172, 147, 168, 163, 166, 139, 158, 151, 137, 140, 138, 137, 158, 133, 144, 144 Assuming that the distribution is normal, what can be concluded at the αα = 0.10 level of significance? A.)For this study, we should use Select an answer t-test for a population mean z-test for a population proportion B.)The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer < = ≠ > H1:H1: ? μ p Select an answer > < ≠ = C.)The test statistic ? z or t = ____ (please show your answer to 3 decimal places.)
- Problem 1: In 2008, data from the Center for Disease Control revealed that 28.5% of all male teenagers, aged 18-19 and attending U.S. colleges were overweight. The definition of overweight is a body mass index (BMI) of over 25. In 2019, a professor in public health at a major university wanted to determine whether that proportion had decreased since 2008. So, he sampled 800 randomly selected incoming male freshman at universities around the country. Using the BMI measurements, he found that 210 of them were overweight. Test the professor’s claim at an α = 0.05 level of significance, the proportion of obese male teenagers in American colleges decreased. Make sure that any necessary assumptions for conducting the hypothesis test are satisfied. A) State the null and alternative hypothesis. H0: Ha: B) Determine the critical value(s) for the test. C) Compute the test statistic (show…Question 9 The third quartile salaries of employees at a company is $70,000. How many employees make more than $70,000? Question 9 options: 75% of Employees 25% of Employees 10% of Employees None of the Employees make more than $70,0004. As part of the study described in Problem 6, investigators wanted to assess the accuracy of self-reported smoking status. Participants are asked whether they currently smoke or not. In addition, laboratory tests are performed on hair samples to determine presence or absence of nicotine. The laboratory assessment is considered the gold standard, or truth about nicotine consumption. The data are as follows: Nicotine Absent Nicotine Present Self- Reported nonsmoker 90 17 Self -reported smoker 10 50 What is the specificity of self-reported smoking status?A)1B)0.1C)0.84D)0.90
- Question 40 In 2008, 46% of business owners gave a holiday gift to their employees. A 2009 survey of business owners indicated that 35% plan to provide a holiday gift to their employees (Radio, WEZV, Myrtle Beach, South Carolina,) Suppose the survey results are based on a sample of 60 business owners. Part A How many business owners in the survey plan to provide a holiday gift to their employees? Ans. Part B Suppose the business owners in the sample do as they plan. Compute the p-value for a hypothesis test that can be sued to determine if the proportion of business owners providing holiday gifts has decreased from the 2008 level. Part C Using a 0.05 level of…QUESTION 1 Researchers wanted to know the effectiveness of a new anti-venom. A study was conducted on 150 children who had nonlethal scorpion stings. The ages of the children ranged from 6 months to 18 years old. Each child was randomly assigned to receive a shot of the anti-venom or a placebo shot. Researchers recorded whether or not their condition improved over the next four hours. a. Complete the two-way table summarizing the findings. Anti-venom Placebo Total Improved 70 80 Did not improve 60 Total 150 b. Use the study results to complete the following. Round your answer to the nearest tenth of a percent, as needed. Of the children who were given the anti-venom % saw their condition improve. Of the children who were given the placebo % saw their condition improve.Problem 2: The research scenario: Do you think there might be a relationships between people's personality and the profession they pursue? Here's a fictional set of data that explores that question. There are two personality types in the data, 'thinkers' and 'feelers.' There are 3 professions. A chi square analysis says, OK, there is a certain proportion of people who are thinkers overall (you will be calculating that, but is comes directly from the data). Is that same proportion (or close to it) found among each of the three professions? For example, if the population at large is divided into 50% thinkers and 50% feelers, then 50% of each profession would be thinkers and 50% would be feelers. But maybe some professions have 'lopsided' percentages of feelers, or lopsided percentages of thinkers. The following crosstab table shows the "crossed" frequencies for 2 variables: "Myers-Brigg" personality type "T" = "thinking" personality…