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Problem 4.13 Two equal and opposite forces act on the beam. Determine the sum of the moments of the two forces (a) about point P; (b) about point Q; (c) about the point with coordinates x = 7 m, y = 5 m.

Problem 4.13 Two equal and opposite forces act on the beam. Determine the sum of the moments of the two forces (a) about point P; (b) about point Q; (c) about the point with coordinates x = 7 m, y = 5 m.

Classical Dynamics of Particles and Systems
Classical Dynamics of Particles and Systems
5th Edition
ISBN:9780534408961
Author:Stephen T. Thornton, Jerry B. Marion
Publisher:Stephen T. Thornton, Jerry B. Marion
Chapter9: Dynamics Of A System Of Particles
Section: Chapter Questions
Problem 9.26P
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Explain part c please

Problem 4.13 Two equal and opposite forces act on the beam. Determine the sum of the moments of the two forces (a) about point P; (b) about point Q; (c) about the point with coordinates x = 7 m, y = 5 m. P a) EM₂ Z Zo b) EM ² MIN 40 VE 20 40153353 IN Q -2 m- 30° 40 N This is called a couple. due to a 40 N -2 m. 30° P = + 40 v ₂² (4) - 401/²2 (2) = 40√3 = 69 N·m Ro (7,5) 401/2 2 12015) - 20 (5) = + 40 1/²2 (2) = 40√3 = 69 N.m -X R √√3 c) EM = 40 (5) + 2065) - H0V (3) 265) z 2 = 40 1/² (5-3) = 40√3 69 №.m - 4 The sum of moments couple is the same about any point.
Transcribed Image Text:Problem 4.13 Two equal and opposite forces act on the beam. Determine the sum of the moments of the two forces (a) about point P; (b) about point Q; (c) about the point with coordinates x = 7 m, y = 5 m. P a) EM₂ Z Zo b) EM ² MIN 40 VE 20 40153353 IN Q -2 m- 30° 40 N This is called a couple. due to a 40 N -2 m. 30° P = + 40 v ₂² (4) - 401/²2 (2) = 40√3 = 69 N·m Ro (7,5) 401/2 2 12015) - 20 (5) = + 40 1/²2 (2) = 40√3 = 69 N.m -X R √√3 c) EM = 40 (5) + 2065) - H0V (3) 265) z 2 = 40 1/² (5-3) = 40√3 69 №.m - 4 The sum of moments couple is the same about any point.
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