Problem #4 Suppose you are interested in studying whether lighting brightness affects spatial reasoningabilities. You decide to test spatial reasoning using completion time scores for the paper-foldingtest with five people, repeating the test on each person with three different lighting levels (800,1,000, and 1,200 lux).In this experiment, the null hypothesis is that:O The completion time mean for at least one lighting brightness is different from anothero There are no individual differences in the completion time meanso There are no differences in the mean completion times among the lighting levelscomparedThe factor of interest is thetheThe results of the study are presented in the following data table. All scores are times necessary tocomplete the paper-folding task, recorded in seconds.Participant 800 luxABсDELighting Brightness1,000 lux3.423.193.503.753.90T = 17.76SS=0.3115ANOVA TableSourceBetween treatmentsWithin treatmentsBetween subjectsErrorTotalSS3.403.523.704.124.16▼Iand the dependent variable isT = 18.90T = 17.84SS = 0.4784 SS = 0.1803df141,200 lux3.503.273.543.833.70The three treatments in the experiment define three populations of interest. You use an ANOVA totest the hypothesis that the three population means are equal. Present the results of your analysisin the following ANOVA table by entering the missing df values and selecting the correct values forthe missing SS, MS, and F entries. (Note: For best results, retain at least two additional decimalpoints throughout your calculations. Depending on the order in which you do these calculationsand the number of digits you retain, you may find slight rounding differences in the last digitbetween your answers and the answer choices.)MSParticipantTotals0.08090.2157P = 10.32P = 9.98P = 10.74P = 11.70P = 11.76n =k =NGΣΧ2 =F==531554.5(199.14 F DistributionNumerator Degreesof Freedom = 26DenominatorDegrees of Freedom= 260.500011.00.500023468FUse the Distributions tool to find the critical value for a = 0.05. The critical value is F =At a significance level of a = 0.05, evaluate the null hypothesis that the population means for alltreatments are equal. The null hypothesis isYouconclude thatlighting brightness affects spatial reasoning abilities.

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Anova is the measure of parametric test. It explain the mean significance between the three or more…