Problem 7-25: Determine the maximum shear stress acting at section a-a of the cantilevered strut. 250 mm- -250 mm 1 2 kN 4 kN 20 mm 300 mm- 70 mm 20 mm 50 mm
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- , Solve the preceding problem using the numerical data: /) = 90mm, h = 280 mm, d = 210 mm, q = 14 kN/m, and L = L2 m.The shear stresses t in a rectangular beam arc given by Eq. (5-43): in which Fis the shear force, / is the moment of inertia of the cross-sectional area, /lis the height of the beam, and i] is the distance from the neutral axis to the point where the shear stress is being determined (Fig. 5-32). By integrating over the cross-sectional area, show that the resultant of the shear stresses is equal to the shear force V.What is the maximum possible value of the clamping Force C in the jaws of the pliers shown in the figure if the ultimate shear stress in the 5-mm diameter pin is 340 MPa? What is the maximum permissible value of the applied load P to maintain a factor of safety of 3.0 with respect to failure of the pin?
- The state of stress on an element along the hydraulic lift cylinder on a truck is trv= — 5 MPaLFind the maximum shear stress on the clement and show the state of stress on a sketch of a properly oriented clement.A circular pole is subjected to linearly varying distributed force with maximum intensity t0. Calculate the diameter daof the pole if the maximum allowable shear stress for the pole is 75 M Pa.Repeat the previous problem using ? = 50° and stresses on the rotated element: sy1= 70 MPa, ??y1=-82 MPa, and tx1y1=-35 MPa.
- The flywheel causes a completely reverse bending on the shaft and the factor of safety is 2, determine: a. The ultimate tensile strength ( Su) of the material if the Yield strength (Sy) is 0.6 of Ultimate strength. b. The fatigue life of the shaft given the fatigue strength (S) is equal to 0.8Su and endurance Strength (Se) is equal to 0, 5Su, given the minimum stress is 0.3 of Maximum stress c. Draw the S - N diagramThe flywheel causes a completely reverse bending on the shaft and the factor of safety is 2, determine: a. The ultimate tensile strength (Su) of the material if the Yield strength (Sy) is 0.6 of Ultimate strength. b. The fatigue life of the shaft given the fatigue strength (Sf) is equal to 0.8 Su and endurance Strength (Se) is equal to 0,5 Su, given the minimum stress is 0.3 of Maximum stress c. Draw the S-N diagramA damper square mat is supporting a dead load weight of8 kN. Helical springs will be used to support the loadlocated at all corners with shearing stress of 120.6 Mpaat 20 turns. The spring has a deformation of 98.7 mmwith a mean radius of 80 mm. Design the minimumdiameter of the wire to support a load. Use G = 83 Gpa.
- 4. The bicycle axle shown below supports the weight of the frame on each side of 800 N. The axle is a hollow steel ( = 300 MPa) tube with inner and outer diameters 10 mm and 7.1 mm. The axle is supported by two ball bearing races in the hub shell. The quick-release mechanism creates an axial clamping force of 2800 N. (a) Draw the shear and bending moment diagrams and determine the values of M and V at critical points. (b) Analyze a point on the bottom of the axle just to the right of the bearing at point C. Calculate the safety factor against yielding using the maximum shear stress criterion. (c) Now analyze a point on the side of the axle just to the right of the bearing at point C. Calculate the safety factor against yielding using the maximum shear stress criterion. (If relevant) A clearly labeled diagram (or diagrams) about your analysis with a coordinate system and relevant labels. Final answer with appropriate units and significant figures. You can use the fprintf()…9-18 A rectangular vertical member fixed at the base is loaded as shown in the figure. Find the location for a gage on member face AB such that no longitudinal strain would occur due to the application of force P = 6 kN. Does the answer depend on the magnitude of force P? Assume elastic behavior. All dimensions are given in mm.Q-1 ) A thin cylinder of inner radius 150 mm and thickness 9 mm is subjected to an internal pressure of 9 MPa. The average circumferential (hoop) stress in MPa isa) 150 MPA b ) 125 MPa c) 175 MPa d ) 200 MPa e) none of these