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Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity Vy. What should be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vinitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay Substituting ay = -g then simplifying results to t= sqrtt which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt Substituting the time taken by the package to reach to ground results to: dx = ( ( sqrt ( which is the expression for the horizontal distance at which you should drop the package.

Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity Vy. What should be the expression for the horizontal distance dy at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vinitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay Substituting ay = -g then simplifying results to t= sqrtt which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt Substituting the time taken by the package to reach to ground results to: dx = ( ( sqrt ( which is the expression for the horizontal distance at which you should drop the package.

College Physics
College Physics
1st Edition
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter2: Kinematics
Section: Chapter Questions
Problem 44PE: A rescue helicopter is hovering over a person whose boat has sunk. One of the rescuers throws a life...
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In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity vx. What should be the expression for the horizontal distance dx at which you release the relief package so that it will arrive to the survivors at the right place? (Neglect the effect of air resistance)

QUESTION 4 Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vịnitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay Substituting ay = -g then simplifying results to t= sqrt which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt Substituting the time taken by the package to reach to ground results to: dx = ( ( sqrt ( )) which is the expression for the horizontal distance at which you should drop the package.
Transcribed Image Text:QUESTION 4 Problem In a relief operation mission involving a helicopter h distance above the ground traveling with a horizontal velocity arrive to the survivors at the right place? (Neglect the effect of air resistance) Solution To determine this, we must first derive the time it takes for the relief package to reach the survivors. We use this equation -h = Vịnitial-yt + (1/2)ay If we just drop the package from the helicopter, the equation above becomes + (1/2)ay Substituting ay = -g then simplifying results to t= sqrt which is the time it takes for the object to reach the ground. Since the package will just travel at a constant velocity in the x-axis, thus dx = Vxt Substituting the time taken by the package to reach to ground results to: dx = ( ( sqrt ( )) which is the expression for the horizontal distance at which you should drop the package.
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