Since the ball was launched horizontally, we know the vertical component of the initial velocity must be zero. Therefore, vy,o = 0 and vz,0 = Vo. This reduces the projectile motion equations to: y = -}gt x = v,t. and (Keep the negative sign on the right hand side of the first equation, since your measurement of y is negative.) Eliminate the unknown t between these two equations, and obtain an expression for v, in terms of x, y, and g.

Since the ball was launched horizontally, we know the vertical component of the initial velocity must be zero. Therefore, vy,o = 0 and vz,0 = Vo. This reduces the projectile motion equations to: y = -}gt x = v,t. and (Keep the negative sign on the right hand side of the first equation, since your measurement of y is negative.) Eliminate the unknown t between these two equations, and obtain an expression for v, in terms of x, y, and g.

Name: I keep trying to combine these equations but whenever I do so I get a
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Description: I keep trying to combine these equations but whenever I do so I get a negative in the square root. Please help. Since the ball was launched horizontally, we know the vertical component of the initial velocitymust be zero. Therefore, vy,o = 0 and vz,0

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter3: Motion Along A Straight Line

Section: Chapter Questions

Problem 113CP: The position of a particle moving along the x -axis varies with time according to x(t)=5.0t24.0t3 ....

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