9:31 DhO N ll 97%20220331_200252.jpgPhoblims84 In Drovphila a chros was made buetween females ell enpreningthe 3X- linkage, recuesive thaits, Slut bristus (sc), Scale body (5)and vermillion eye (v) and wild type males. On the FI, ellfemalis cuere wild type whil all mals enprunid ell the matonttraits.The Chos was labrid to the F2 generation Ond 1000 offspringwere countid arith resalt shoued beloo:PhonatypeSe S VSet st yt.Set s v-Sc st v+Sc st vSct s vt.s vt.31428015646301014Scsct st v-To00Uing the nommelature, detumine genatyps of Pond Fl patnt.D Osder f genes ond mapdistonce.9 Aru there moto or fuver double crou thon onfectidD aleulate the Caeffeicint of Coincidence.62 Femole hutrazygous for ehony le/e), searlit (st"/st)end spineles sst/ss) were itest chomud ord the following Fpraginy wrere olitainid:-Preginy PhenolyptWild typee st ss- et st ss.-678.68347 Spiniless - e st sstScarlt fineles - e st soEbonyEbony seorlet- ct set ssEhgrny spinehs- et st sst-Ebony rearlet -et st'sstspinelessScerit7854-e sttss368

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Problems a cros was made between fomales all enprening 84 In Droephila the 3 X- Jinkage, rucusive traits, Slut hrists (sc), Scale body (s) and vermillion eye (v) and wild typt mals. On the FI, all Lumalis cuure aild type whil all malis eyprUmid oll the matort tait. the Ches was dabrid to the F2 generation Ond 1000 offipring cuere countid arith result,shoued beloo: Phinatype Se S V. Set st yt. Set s v- Sc st v+. Se st v- Sct s vt. Se S vt. 314 280 156 46 30 10 Set st v. 14 Uing the nomenelature, detrmins genatype of Pond FI parnt. D Osrder of genes ond mopdistonce. 9 Aru theri mou or fuwer 8 double troy thon Onfectid O Caleulati the Coufficient of loincidence. 1000

Problems a cros was made between fomales all enprening 84 In Droephila the 3 X- Jinkage, rucusive traits, Slut hrists (sc), Scale body (s) and vermillion eye (v) and wild typt mals. On the FI, all Lumalis cuure aild type whil all malis eyprUmid oll the matort tait. the Ches was dabrid to the F2 generation Ond 1000 offipring cuere countid arith result,shoued beloo: Phinatype Se S V. Set st yt. Set s v- Sc st v+. Se st v- Sct s vt. Se S vt. 314 280 156 46 30 10 Set st v. 14 Uing the nomenelature, detrmins genatype of Pond FI parnt. D Osrder of genes ond mopdistonce. 9 Aru theri mou or fuwer 8 double troy thon Onfectid O Caleulati the Coufficient of loincidence. 1000

Biology: The Unity and Diversity of Life (MindTap Course List)

15th Edition

ISBN:9781337408332

Author:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Publisher:Cecie Starr, Ralph Taggart, Christine Evers, Lisa Starr

Chapter13: Observing Patterns In Inherited Traits

Section: Chapter Questions

Problem 8GP: In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive...

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In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
14. A wildtype fruit fly (heterozygous for gray body and normal wings) is mated 2 poin with a black fly with vestigial wings. Offspring: 778-wild type 785-black vestigial 158-black-normal wings 162 gray body-vestigial wings. 1. What is the recombination frequency between these genes? 2. Are the genes linked? Explain why or why not. *
In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive allele for red flowers (p). An allele for Jang pollen grains (L) is dominant when paired with a recessive allele for round pollen grains (L). Bateson and Punnett crossed a plant having purple flowers and long pollen grains with one having white flowers and round pollen grains. All F1 offspring have purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple /lower/ round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?
In sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive allele for red flowers (p). An allele for Jang pollen grains (L) is dominant when paired with a recessive allele for round pollen grains (L). Bateson and Punnett crossed a plant having purple flowers and long pollen grains with one having white flowers and round pollen grains. All F1 offspring have purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple /lower/ round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?
The phenotype of individuals heterozygous for ________ alleles comprises both homozygous phenotypes. a. epistatic b. codominant c. pleiotropic d. hybrid
A mutated allele responsible for Marfan syndrome (Section 13.5) is inherited in an autosomal dominant pattern. What is the chance that any child will inherit it if one parent does not carry the allele and the other is heterozygous for it?
Red-flowering snapdragons are homozygous for allele RI. White-flowing snapdragons are homozygous for a different allele (R2). Heterozygous plants (R1 R2) bear pink flowers. What phenotypes should appear among first-generation offspring of the crosses listed? What are the expected proportions for each phenotype? a. R1R1 R1R2 b. R1R1 R2R2 c. R1R2 R1R2 d. R1R2 R2R2
A single allele gives rise to the Hbs form of hemoglobin. Individuals who are homozygous for the allele (HbS/HbS) develop sickle-cell anemia (Section 9.6). Heterozygous individuals (HbA/HbS) have few symptoms. A couple who are both heterozygous for the HbS allele plan to have children. For each of the pregnancies, state the probability that they will have a child who is: a. homozygous for the HbS allele b. homozygous for the normal allele (HbA) c. heterozygous: HbA/HbS
Another gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?
The ABO blood groups in humans are expressed as the IAlB, and IAalleles. The allele encodes the A blood group antigen, lBencodes B, and i encodes O. Both A and B are dominant to O. If a heterozygous blood type A parent (IAi) and a heterozygous blood type B parent (IBi) mate, one quarter of their offspring will have AB blood type (IAIB) in which both antigens are expressed equally. Therefore, ABO blood groups are an example of: multiple alleles and incomplete dominance codominance and incomplete dominance incomplete dominance only multiple alleles and codominance
0. In Drosophila, the gene for cinnabar eye color is onchromosome 2, and the gene for scarlet eye color is onchromosome 3. A fly homozygous for both recessivecinnabar and scarlet alleles (cn/cn; st/st) is white-eyed.a. If male flies (containing chromosomes with thenormal gene order) heterozygous for cn and st allelesare crossed to white-eyed females homozygous forthe cn and st alleles, what are the expected phenotypes and their frequencies in the progeny?b. One unusual male heterozygous for cn and st alleles,when crossed to a white-eyed female, produced onlywild-type and white-eyed progeny. Explain the likelychromosomal constitution of this male.c. When the wild-type F1 females from the cross withthe unusual male were backcrossed to normal cn/cn;st/st males, the following results were obtained:wild type 45%cinnabar 5%scarlet 5%white 45%Diagram a genetic event at metaphase I that couldproduce the rare cinnabar or scarlet flies among theprogeny of the wild-type F1 females.
5. In the fruit fly Drosophila melanogaster, very dark(ebony) body color is determined by the e allele. Thee+ allele produces the normal wild-type, honeycolored body. In heterozygotes for the two alleles (butnot in e+e+ homozygotes), a dark marking called thetrident can be seen on the thorax, but otherwise thebody is honey-colored. The e+ snd e alleles are thusconsidered to be incompletely dominant.a. When female e+e+ flies are crossed to male e+eflies, what is the probability that progeny will havethe dark trident marking?b. Animals with the trident marking mate amongthemselves. Of 300 progeny, how many would beexpected to have a trident, how many ebony bodies, and how many honey-colored bodies?