Process of inserting an element in stack is called ____________ a) Create b) Push c) Evaluation d) Pop
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Process of inserting an element in stack is called ____________
a) Create
b) Push
c) Evaluation
d) Pop
Step by step
Solved in 2 steps
- Assume s1,s2 are two stacks and we write s1=s2 , if the class stack based on array then إختر أحد الخيارات: a. This statement is good to use when s1 has small number of items b. This statement is good to use when s2 has large number of items c. This statement is good to use when s2 has small number of items d. This statement is good to use when s1 has large number of items أخلِ اختياريFor this code just explain the void pop function, with enough explanation that how it is working. Also explain on the usage of pointer in this function. Thanks #include<iostream> using namespace std; int choice, j=0;int stack[50];int *top;bool Exit_Indicator = false; void displayStack() { cout << "\n\t~Stack Display~\nTOP ->"; for (int i = j-1; i >= 0; i--) cout << "\t|\t" << stack[i] << "\t|" << endl; cout << "\t-----------------";} void push(int i){ cout << "\n(" << i << ") has been PUSHED into the stack!"; *top = i; top++; j++;} void pop(){ if((*(top-2) != 0 && *(top-1)!= 0) || (*(top-2) == 0 && *(top-1)!= 0)) { cout << "\n(" << *(top-1) << ") has been POPPED from the stack!"; *(top-1)= 0; top--; j--; } else{ cout<<"\nTHE STACK IS EMPTY";}} int main() { int value; top = stack; do { cout <<…Stacks 1- Write a Python function that takes a user input of a word and returns True if it is a Palindrome and returns False otherwise (Your function should use a Stack data structure). A palindrome is a word that can be read the same backward as forward. Some examples of palindromic words are noon, civic, radar, level, rotor, kayak, reviver, racecar, redder, madam, and refer. 2- Write a Python function that takes a stack of integer numbers and returns the maximum value of the numbers in the stack. The stack should have the same numbers before and after calling the function. 3- Write a main function that tests the functions you wrote in 1 and 2 above and make sure that your code is well documented.
- For this code, just explain the void pop function, with each and every line. And please provide enough information on how it is working. #include<iostream> using namespace std; int choice, j=0;int stack[50];int *top;bool Exit_Indicator = false; void displayStack() { cout << "\n\t~Stack Display~\nTOP ->"; for (int i = j-1; i >= 0; i--) cout << "\t|\t" << stack[i] << "\t|" << endl; cout << "\t-----------------";} void push(int i){ cout << "\n(" << i << ") has been PUSHED into the stack!"; *top = i; top++; j++;} void pop(){ if((*(top-2) != 0 && *(top-1)!= 0) || (*(top-2) == 0 && *(top-1)!= 0)) { cout << "\n(" << *(top-1) << ") has been POPPED from the stack!"; *(top-1)= 0; top--; j--; } else{ cout<<"\nTHE STACK IS EMPTY";}} int main() { int value; top = stack; do { cout <<…C# Reverse the stack - This procedure will reverse the order of items in the stack. This one may NOT break the rules of the stack. HINTS: Make use of more stacks. Arrays passed as parameters are NOT copies. Remember, this is a procedure, not a function. This would occur in the NumberStack class, not the main class. These are the provided variables: private int [] stack;private int size; Create a method that will reverse the stack when put into the main class.For this code just explain the void pop function, with enough explanation that how it is working. Thanks #include<iostream> using namespace std; int choice, j=0;int stack[50];int *top;bool Exit_Indicator = false; void displayStack() { cout << "\n\t~Stack Display~\nTOP ->"; for (int i = j-1; i >= 0; i--) cout << "\t|\t" << stack[i] << "\t|" << endl; cout << "\t-----------------";} void push(int i){ cout << "\n(" << i << ") has been PUSHED into the stack!"; *top = i; top++; j++;} void pop(){ if((*(top-2) != 0 && *(top-1)!= 0) || (*(top-2) == 0 && *(top-1)!= 0)) { cout << "\n(" << *(top-1) << ") has been POPPED from the stack!"; *(top-1)= 0; top--; j--; } else{ cout<<"\nTHE STACK IS EMPTY";}} int main() { int value; top = stack; do { cout <<…
- C# Reverse the stack - This procedure will reverse the order of items in the stack. This one may NOT break the rules of the stack. HINTS: Make use of more stacks. Arrays passed as parameters are NOT copies. Remember, this is a procedure, not a function. public void ReverseStack(){ }C++ code output must be: Enter series of parentheses: Not Balance! What is the problem of this code? #include <iostream>#include <string>#include <vector>#include <stack>using namespace std; int main(){string x;stack<char, vector<char>> iStack;bool status = true;cout << "Enter series of parentheses: ";getline(cin, x); for (int i = 0; i < x.length(); i++) if (x[i] == '(' || x[i] == '{' || x[i] == '[')iStack.push(x[i]);else{ if (x[i] == ']'){if (iStack.empty() || iStack.top() != '['){return false;}}else if (x[i] == ')'){if (iStack.empty() || iStack.top() != '('){return false;}}else if (x[i] == '}'){if (iStack.empty() || iStack.top() != '{'){return false;}}iStack.pop();} if (iStack.empty())cout << "Balance!" << endl;elsecout << "Not Balance!" << endl;}C++ ProgrammingTopic: Stack, Ques and DequesBelow is the initial program of the main file, only modify the main file, sllstack file also provided. See attached photo for instructions. main.cpp #include <iostream> #include <cstring> #include "sllstack.h" using namespace std; int main(int argc, char** argv) { SLLStack* stack = new SLLStack(); int test; string str; cin >> test; switch (test) { case 0: getline(cin, str); // PERFORM SOLUTION TO BRACKETS PROBLEM HERE // FYI: Place your variable declarations, if any, before switch. break; case 1: stack->push('a'); stack->push('b'); stack->push('c'); cout << stack->pop() << endl; cout << stack->pop() << endl; cout << stack->pop() << endl; cout << stack->isEmpty() << endl; break;…
- assembly language ctt 9. Counting Nearly Matching ElementsWrite a procedure named CountNearMatches that receives pointers to two arrays of signed doublewords, a parameter that indicates the length of the two arrays, and a parameter that indicates the maximum allowed difference (called diff) between any two matching elements. For each element x(i) in the first array, if the difference between it and the corresponding y(i) in the second array is less than or equal to diff, increment a count. At the end, return a count of the number of nearly matching array elements in EAX. Display this value. Write a test program that calls CountNearMatches and passes pointersto two different pairs of arrays. Use the INVOKE statement to call your procedure and pass stackparameters. Create a PROTO declaration for CountMatches. Save and restore any registers (other than EAX) changed by your procedure.True or False For each statement below, indicate whether you think it is True or False. If you like, you can provide a description of your answer for partial credit in case you are incorrect. Given a stack implemented as an array, and the following functions performed: Push(A), Push (B), Push(C), Pop(), Push(D), Push(E), Pop(), Push(F) The array will be [A][B][D][F] and the “top” of the stack will be at index 3 where [F] is The next element that will be removed when Pop is called will be A If we Push(G), [G] will be inserted at index 0 Given a queue implemented as an array with a maximum capacity of 5 elements and O(1) insert and remove, and the following functions are performed: Insert(7), Insert(6), Insert(5), Insert(4), Remove(), Remove(), Insert(3), Insert(2), Insert(1), Remove() The removeIndex value will be index 4 The array will be [2][1][ ][4][3] The insertIndex value will be index 2 Given a priority queue implemented as a standard linked list with only a…struct Faculty { int id; char name[30]; char status[10]; //status permanent or visiting Faculty next; }; Assume we have three stacks S, V and P. S is a stack having mix data of visiting and permanent faculty members, V is empty and for visiting faculty memebrs and P is also empty for permanent faculty members. Using primitive functions of stack write a C++ code which reads entire data from S and write on respective stack V or P.