Program No. 0 1 2 3 4 Base 1220 2300 90 Second Page of Progo form 480 3. (24 points=6+2+6+6+1+1+2) operating system uses frames of size 512 bytes. 2000 a. The programs must be split into pages of for: Prog 0 We are using a demand paging model in this question. Our Length 768 1536 384 512 Progl Prog2 Prog 3 Prog 4 b. What is the minimum number of frames that you need in order to have the smallest number o page faults irrespective of the order in which your system will process the interrupts. 256 bytes. Give the number of frames needed c. Now assume that at a certain instant you have five frames and they are loaded with the following pages: Third Page First Page Of Progl Of Prog4 Give the indicated address following logical address: 1500 in Progl in pto form , in f+0 form First Page Of Prog3 First Page Of Prog2 in absolute physical address d. Under the same circumstances as in Part c, give the logical addresses corresponding to the following physical addresses 2000 in fto form p+o form e. What is the lowest invalid logical address in Prog2 f. Is there any external fragmentation? g. Is there any internal fragmentation. If so give an example and state how many bytes?

explain this program  bus1:mov ax,400add amount, axmov dx,0mov bx,10mov cx,0l222:div bxpush dxmov dx,0mov ah,0inc cxcmp ax,0jne l222l333:pop dxadd dx,48mov ah,2int 21hloop l333;mov am3,amount inc countinc bjmp while_jmp end_ recrd procmov dx,offset msg7mov ah,9int 21h ; print here the whole amountmov ax, amount mov dx,0mov bx,10mov cx,0

please help. this will be a matlab code

Let's say p contains a memory address and the 8 bytes in memory beginning at that address are (in hex): 01 12 23 34 45 56 67 78. If p's type is "uint32_t *", what is the value of x on a little-endian computer after executing: uint32_t x = p[0]; Ox01122334 Ox0112233445566778 Ox34231201 Ox7867564534231201 O O O O