PROGRAMMING EXERCISES: 4. How many double entries can aValues[MAX_A] store? 5. What is the value of aValues[2]? [Hint: the value is an address] 6. How many bytes are allocated to sentence?
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4. How many double entries can aValues[MAX_A] store?
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- In C++ struct myGrades { string class; char grade; }; Declare myGrades as an array that can hold 5 sets of data and then set a class string in each position as follows: “Math” “Computers” “Science” “English” “History” and give each class a letter gradeC++ Struct Pointers Help: I have a file called names.txt. Write a program that reads each line and then store the name and nickname under an individual pointer to the class Person. names.txt: Norman, Normie Justine, Jussy Richard, Dick Shelley, Shell class Person { public: string name; string nickname; Person(string name, nickname) { this->name=name; this->nickname = nickname; } }; Print out each pointer's name and nickname to verify that it has been stored.assembly language ctt 9. Counting Nearly Matching ElementsWrite a procedure named CountNearMatches that receives pointers to two arrays of signed doublewords, a parameter that indicates the length of the two arrays, and a parameter that indicates the maximum allowed difference (called diff) between any two matching elements. For each element x(i) in the first array, if the difference between it and the corresponding y(i) in the second array is less than or equal to diff, increment a count. At the end, return a count of the number of nearly matching array elements in EAX. Display this value. Write a test program that calls CountNearMatches and passes pointersto two different pairs of arrays. Use the INVOKE statement to call your procedure and pass stackparameters. Create a PROTO declaration for CountMatches. Save and restore any registers (other than EAX) changed by your procedure.
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- #ifndef lab5ExF_h #define lab5ExF_h typedef struct point { char label[10]; double x ; // x coordinate for point in a Cartesian coordinate system double y; // y coordinate for point in a Cartesian coordinate system double z; // z coordinate for point in a Cartesian coordinate system }Point; void reverse (Point *a, int n); /* REQUIRES: Elements a[0] ... a[n-2], a[n-1] exists. * PROMISES: places the existing Point objects in array a, in reverse order. * The new a[0] value is the old a[n-1] value, the new a[1] is the * old a[n-2], etc. */ int search(const Point* struct_array, const char* target, int n); /* REQUIRES: Elements struct-array[0] ... struct_array[n-2], struct_array[n-1] * exists. target points to string to be searched for. * PROMISES: returns the index of the element in the array that contains an * instance of point with a matching label. Otherwise, if there is * no point in the array that its label matches the target-label, * it should return -1. * If there are more than…1. Write a C++ function named "extractDebugOption" that accepts arguments similar to argc (an integer for the array size) and argv (an array of pointers to C-string). It will determine whether it has the argument of "/debug yes" or "/debug no". It will return true if the debug option is yes. If "/debug no" or there is no debug option or "/debug" without "yes" or "no" followed, it will return false. Note: command line arguments are simply an array of pointers to C-string. Please test it with the following command line arguments These will return true"/debug yes""/compile /debug yes" These will return false"/debug no""/debug""debug""yes /debug""no /debug"C++ Language C++ Code not working, what is the missing piece in this code? #include <iostream>#include <string>#include <vector>#include <stack>using namespace std; int main(){string x;stack < char, vector<char> > iStack;boolean status=true; cout << "Enter series of parentheses: ";getline(cin, x);for (int i=0; i<x.length(); i++)//measure the length of the string inputif (x[i] == '(' || x[i] == '{' || x[i] == '[')iStack.push(x[i]);else{ //if not opening grouping symbolif(x[i] == ']') {if(iStack.isEmpty() || iStack.top() != '[') {return false;}} else if (x[i] == ')') {if(iStack.isEmpty() || iStack.top() != '(') {return false;}} else if (x[i] == '}') {if(iStack.isEmpty() || iStack.top() != '{') {return false;} }iStack.pop();} if (iStack.empty())cout << "Balance!" << endl;elsecout << "Not Balance!" << endl;}
- In C program Define a structure type to represent a common fraction. Write a program that gets a fraction and displays both the fraction and the fraction reduced to lowest terms using thefollowing code fragment: frac = get_ fraction(); print_ fraction( frac); printf(" = "); print_ fraction( reduce_ fraction( frac)); You can use Euclid's algorithm to find (gcd) of two integers: gcd(m,n) = n (if n divides m with no remainder), otherwise gcd(m,n) = gcd(n,remainder(m/n)) For example: If you enter: 12/8 then the program output should be: 12/8 = 3/2 If you enter: 3/2 then the program output should be: 3/2 = 3/2 If you enter: 8/4 then the program output should be: 8/4 = 2/1python: def character_dict(prof_dict):"""Question 2- Given a dictionary that maps a character to a list of professors they want totalk to, return a dictionary withthe value being the list sorted by the last letter in each professors' last name.- If two professors have the same last letter of their last name, sort by the first letter of their first name.- THIS MUST BE DONE IN ONE LINEArgs:prof_dict (dict)Returns:dict>>> character_dict({"Harry": ["Albus Dumbledore", "Minerva McGonagall", "Severus Snape", "Rubeus Hagrid"], "Hermione": ["Remus Lupin", "Alastor Moody", "Horace Slughorn"]}){'Harry': ['Rubeus Hagrid', 'Albus Dumbledore', 'Severus Snape', 'Minerva McGonagall'], 'Hermione': ['Horace Slughorn', 'Remus Lupin', 'Alastor Moody']}>>> character_dict({"Scorpius": ["Severus Snape", "Dolores Umbridge", "Horace Slughorn"], "Neville": ["Cuthbert Binns", "Rubeus Hagrid", "Minerva McGonagall"]}){'Scorpius': ['Dolores Umbridge', 'Severus Snape', 'Horace Slughorn'],…The main method in C which calls all the above functions is: #include<stdio.h>int main(){ int s1[100], s2[100], n, m, result[200]; scanf("%d",&n); scanf("%d",&m); initialize(); //initializes the set s1 initialise(); //initializes the set s2 display(Set s1); //displays the elements of set s1 display(Set s2); //displays the elements of set s2 addNode(Set s1, int n); // add element n into the set s1 contains(Set s1, int m); // search for element m in the set s1 getUnion(Set result, Set s1, Set S2); intersection(Set result, Set s1, Set s2); difference(Set result, Set s1, Set s2); symmetric difference(Set result, Set s1, Set s2); subset(Set s1, Set s2); disjoint(Set s1, Set s2); equal(Set s1, Set S2);return 0;} Note: Please fix some of the functions cause it causes run time error, I have already used up 2 follow up questions on this, Please Send an image of a sample run and output of this code please, and find out why it wont run and modify some of the…