Propane (g) and oxygen (g) are introduced into a container at 300°C to produce carbon dioxide (g) and water (l) at 60°C. to ensure complete decomposition of the propane, a 35% excess air is used in the feed. What is the total heat generated?
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- A hydrocarbon stream composed of 40 mol% n-butane and 60 mol% n-octane is fed at 100 kmol/h to a flash vessel operating at 5 bar and 145°C. The liquid outlet stream of the flash vessel is then sent to a distillation column with a partial condenser to further separate the components. 90% of the butane in the feed to the column is recovered in the overhead vapor product (distillate), along with small amounts of octane. The bottoms product contains octane which accounts for 75% of the octane in the fresh hydrocarbon feed (to the flash vessel). The condenser and reboiler operating temperatures are 136.7°C and 165.7°C, respectively. Determine the compositions of the liquid outlet stream of the condenser and the vapor outlet stream of the reboiler.Fruit juices at 30 ° C containing 5% total solids were concentrated via a single effect evaporator. The evaporator is operated in a vacuum at an evaporation temperature of 80 ° C, and 90% quality steam is supplied at 169.06 kPa. The desired concentration of the final product is 40% total solids. The rate of concentrated product leaving the evaporator is 2000 kg / hour. The specific heat of fruit juice is 4.05 kJ / (kg ° C), and the concentrated product is 3,175 kJ / (kg ° C). Count a. The required steam rate is = Answerkg / hour. b. Steam economy when the condensate temperature is released at 90 ° C. = Answer(kg of water evaporated / kg of steam)Fruit juices at 30 ° C containing 5% total solids were concentrated via a single effect evaporator. The evaporator is operated in a vacuum at an evaporation temperature of 80 ° C, and 90% quality steam is supplied at 169.06 kPa. The desired concentration of the final product is 40% total solids. The rate of concentrated product leaving the evaporator is 2000 kg / hour. The specific heat of fruit juice is 4.05 kJ / (kg ° C), and the concentrated product is 3,175 kJ / (kg ° C). a. The required vapor rate is = kg / hour. b. Steam economy when the condensate temperature is released at 90 ° C. = (kg of water evaporated / kg of steam)
- A mixture containing 42 wt% benzene (B) and 58 wt% toluene (T) is fed to a distillation column at a flow rate of 100 kg per minute. The product steam leaving the top of the column (the overhead product) contains 90 wt% benzene and 85 wt% of the total benzene fed to the column exits in this overhead product stream. Calculate the mass flow rate and mass composition of the product stream leaving the bottom of the column. Calculate the volumetric flow rate of the overhead product, assuming that it exits the distillation column as a vapour stream at 82C and 1 atm (abs). Physical Property Data (S.G.= specific gravity) from table B-1: Benzene S.G. = 0.879 MW = 78.11 g/mol Toluene S.G. = 0.866 MW = 92.13 g/mol Water Density = 1.00 kg/L MW = 18.02 g/mol R = 0.08206 L atm/mol KL-lysine is produced by Corynebacterium glutamicum in a bioreactor using glucose as the carbon source and ammonia as the nitrogen source. All streams of this process are aqueous. In the inflow, 8 grams of glucose per 100 grams of flow fluid flowing at a rate of 500 kg / hour is included. The glucose flow rate in the exit steam is 1 kg / hour. The reaction takes place at 25 °c.What is the mole percentage of glucose that was consumed during cell growth inside the bioreactor? -Does the growth of Corynebacterium glutamicum cells inside this bioreactor release or absorbheat? Should heat be supplied to the bioreactor, or removed from, to maintain the operation temperature? I want the solution of both options.Cereal is being dried in a vertical drier by air flowing countercurrent to the cereal. To prevent breakage of the cereal flakes, some of the exit air from the drier is recycled back to mix with the the moist fresh air. For each 1000 kg/hr of wet cereal fed to the drier, calculate the input of moist fresh air in kg/hr and recycle rate in kg/hr. The available data on stream compositions is (fractions): For water: Fresh air: 0.0132 Wet cereal: 0.200 Exit air: 0.263 Dried Cereal: 0.050 Air entering Dryer: 0.066
- Exhaust steam from a steam power plant in Batangas is at 7 kPa(29°C) at the rate of 75 kg/s enters a single pass condenser containing 5,780 pcs copper tubes with a total surface area of 2950 m2. The steam has a moisture content of 10% (hf = 163.4 kJ/kg & hfg = 2572.5 kJ/kg) and the condensate leaves saturated liquid at steam temperature. The cooling water flow rate is 4.413 m3/s entering at 20°C. Size of tubes, 25 mm O.D. by 3 mm thick wall. Find the overall heat transfer coefficient.- The major objective of a roasting process is to eliminate the Sulphur contained in the concentrate andto provide a calcine. In a roasting plant, 1000 kg per hour of molybdenum(IV) sulphide (MoS2) is roastedwith 25 % excess air to obtain MoO3 calcine in a chamber-type roasting furnace. Preheated air entersthe reactor at 400 K while MoS2 enters at room temperature. After the process, the waste gases leavethe reactor at 1000 K, and the calcine leaves at 850 K.a) Draw process flowsheet and heat balance diagram (ref. temp is 298 K) b) Calculate the amount of off-gas per hour in moles. c) Calculate the amount of calcined MoO3 per hour in kg.Meztiza, a beer cocktail, is prepared by mixing rum, beer, and cola. Compute the finalconcentration(%w/v) of ethanol in meztiza if 100.0 mL of beer was first mixed with 5.0 mL rum andbefore finally diluting it with cola to produce 200.0 mL of the beer cocktail. ( a beer contains about 4.50% (v/v) of ethanolfermented by yeast from sugars while rum contains about 40.0% (v/v) ethanol. Meanwhile, arubbing alcohol is also an alcohol solution which contains 70.0 %(v/v) isopropyl alcohol fermentedby a bacterium instead of a yeast)
- A single effect evaporator is used to concentrate 10 000 kg / hr of tomato juice from 5% total solids to 30% total solids. The juice enters the evaporator at 15 ° C. The evaporator is operated on Steam (80% quality) at 143.27 kPa. The vacuum in the evaporator allows the juice to boil at 75 ° C. The specific heat of the dilute material is 4.1 kJ / (kg ° C) and the concentrate product is 3.1 kJ / (kg ° C). Count it (a) Steam demand rate = Answer kg / hour. b. Steam economy when condensate temperature is released at 75 ° C. = Answer (kg of water evaporated / kg of steam)For the equilibrium system: H2O(g) + CO(g) <--> H2(g) + CO2(g). Delta heat of rxn: -42 kJ/mol and Kc=0.62 at 1260 K.0.10 mol each of water, CO, and CO2 (all at 1260 K) are placed in a sealed 1.0-Liter thermally-insulated vessel, which is also at 1260 K. When the system comes to equilibrium, which is true?-The temp & mass of CO would increase.-The temp & mass of CO would decrease.-The temp would remain constant & the mass of CO would increase.-The temp would increase and the mass of CO would decrease.-The temp would decrease and the mass of CO would increase.A binary mixture with components A and B is to be separated in a distillation column to obtain 95 mol%. A as the top product. The binary mixture has a con stant relative volatility AB = 2. The column feed is a a - saturated liquid containing 50 mol % of A. Under the usual simplifying assumptions such as constant molal overflow, negligible heat loss, ideal trays, the mini mum reflux ratio for this separation is (rounded off to one decimal place)