PV=nRT R=0.0821 atm L/mol•K STP: 0 °C, 1.0 atm °C+ 273.15 =K NA= 6.022 x1023 An open flask sitting in the fridge looks empty, but we know it contains air. If the flask volume is 2.0OL under STP conditions, how many gaseous molecules does the flask contain? Answer: molecules (Round your answer to 3 significant figures, and put the exponent from scientific notation only in the blank after "E")

Chemistry: Principles and Reactions
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Author:William L. Masterton, Cecile N. Hurley
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Chapter5: Gases
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PV=nRT
R=0.0821 atm•L/mol•K
STP: 0 °C, 1.0 atm
°C + 273.15 =K
NA= 6.022 x1023
An open flask sitting in the fridge looks empty, but we know it contains air. If the flask volume is 2.0OL under STP conditions, how many gaseous molecules does the
flask contain?
Answer:
after "E")
molecules (Round your answer to 3 significant figures, and put the exponent from scientific notation only in the blank
Transcribed Image Text:PV=nRT R=0.0821 atm•L/mol•K STP: 0 °C, 1.0 atm °C + 273.15 =K NA= 6.022 x1023 An open flask sitting in the fridge looks empty, but we know it contains air. If the flask volume is 2.0OL under STP conditions, how many gaseous molecules does the flask contain? Answer: after "E") molecules (Round your answer to 3 significant figures, and put the exponent from scientific notation only in the blank
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