Q 1. In a Newton's ring arrangement with air film observed with the light of wavelength 6× 10* cm, the difference of squares of diameters of successive rings is 0.125 cm?. What will happen to this quantity if: (a)Wavelength of light is changed to 4.5 × 10° cm. (b)A liquid of refractive index 1.33 is introduced between the lens and the plate. (c)The radius of curvature of the convex surface of the plano-convex lens is doubled.

Q 1. In a Newton's ring arrangement with air film observed with the light of wavelength 6× 10* cm, the difference of squares of diameters of successive rings is 0.125 cm?. What will happen to this quantity if: (a)Wavelength of light is changed to 4.5 × 10° cm. (b)A liquid of refractive index 1.33 is introduced between the lens and the plate. (c)The radius of curvature of the convex surface of the plano-convex lens is doubled.

College Physics

10th Edition

ISBN:9781285737027

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter22: Reflection And Refraction Of Light

Section: Chapter Questions

Problem 30P: The index of refraction for crown glass is 1.512 at a wavelength of 660 nm (red), whereas its index...

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A good quality camera “lens” is actually a system of lenses, rather than a single lens, but a side effect is that a reflection from the surface of one lens can bounce around many times within the system, creating artifacts in the photograph. To counteract this problem, one of the lenses in such a system is coated with a thin layer of material (n=1.28) on one side. The index of refraction of the lens glass is 1.68. What is the smallest thickness of the coating that reduces the reflection at 640 nm by destructive interference? (In other words, the coating’s effect is to be optimized for =640 nm .)
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A plano-convex lens has index of refraction n. The curved side of the lens has radius of curvature R and rests on a flat glass surface of the same index of refraction, with a film of index nflim between them, as shown in Figure P36.42. The lens is illuminated from above by light of wavelength . Show that the dark Newtons rings have radii given approximately by r=mRnfilm where r R and m is an integer. Figure P36.42
The index of refraction for crown glass is 1.512 at a wavelength of 660 nm (red), whereas its index of refraction is 1.530 at a wavelength of 410 nm (violet). If both wavelengths are incident on a slab of crown glass at the same angle of incidence, 60.0, what is the angle of refraction for each wavelength?
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