Q. Consider the dining philosophers problem where 5 philosophers are involved. Assume that there are two types of philosophers. The first type named as lefty (L) picks up his left chopstick first and the second type called righty (R) picks up his right chopstick first. The behaviour of a righty is given below. Philosopher i: do{ wait(chopstick[(i+1) % 5]); wait(chopstick[i]); eat signal(chopstick[i]); signal(chopstick[(i+1) % 5]); } State whether the following sets of philosophers seating at the table may lead to a deadlock? Philosophers RRRRR (5 lefty philosophers) RRRLR (4/tighty, one lefty) LLLLL Deadlock / No Deadlock Deadlock No Deadlock Deadlock No Deadlock No Deadlock LLRRR RRLLL RIGHTY
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- Suppose that a manufacturing company builds n different types of robots, sayrobots 1, 2, . . . , n. These robots are made from a common set of m types of materials, saymaterials 1, 2, . . . , m. The company has only a limited supply of materials for each year,the amount of materials 1, 2, . . . , m are limited by the numbers b1, b2, . . . , bm, respectively.Building robot i requires an aij amount from material j. For example, building robot 1requires a11 from material 1, a12 from material 2, etc. Suppose the profit made by sellingrobot i is pi. Write an integer linear program for maximizing the annual profit for thecompanyAnswer the following: This problem exercises the basic concepts of game playing, using tic-tac-toe (noughts and crosses) as an example. We define Xn as the number of rows, columns, or diagonals with exactly n X’s and no O’s. Similarly, On is the number of rows, columns, or diagonals with just n O’s. The utility function assigns +1 to any position with X3=1 and −1 to any position with O3=1. All other terminal positions have utility 0. For nonterminal positions, we use a linear evaluation function defined as Eval(s)=3X2(s)+X1(s)−(3O2(s)+O1(s)). a. Show the whole game tree starting from an empty board down to depth 2 (i.e., one X and one O on the board), taking symmetry into account. b. Mark on your tree the evaluations of all the positions at depth 2. c .Using the minimax algorithm, mark on your tree the backed-up values for the positions at depths 1 and 0, and use those values to choose the best starting move. Provide original solutions including original diagram for part a!Answer the following: This problem exercises the basic concepts of game playing, using tic-tac-toe (noughts and crosses) as an example. We define Xn as the number of rows, columns, or diagonals with exactly n X’s and no O’s. Similarly, On is the number of rows, columns, or diagonals with just n O’s. The utility function assigns +1 to any position with X3=1 and −1 to any position with O3=1. All other terminal positions have utility 0. For nonterminal positions, we use a linear evaluation function defined as Eval(s)=3X2(s)+X1(s)−(3O2(s)+O1(s)). a. Show the whole game tree starting from an empty board down to depth 2 (i.e., one X and one O on the board), taking symmetry into account. b. Mark on your tree the evaluations of all the positions at depth 2. c .Using the minimax algorithm, mark on your tree the backed-up values for the positions at depths 1 and 0, and use those values to choose the best starting move. Provide original solution!
- Using c++ Apply both breadth-first search and best-first search to a modified version of MC problem. In the modified MC, a state can contain any number of M’s and any number of C’s on either side of the river. Assume the goal is always to move all the persons on the left side to the right side. The Initial state should be a parameter given to the program at beginning of execution. As in the original problem, boat capacity =2, the boat cannot move by itself, and on either side C’s should not outnumber M’s. For best-first search, you need to come up with an appropriate heuristic. In addition to solving the problem, your grade will also be based on th effectiveness of the heuristic. As an example, the program should execute as follows. Initial state… Enter number of M’s on left side of the river: 3 Enter number of C’s on left side of the river: 1 Enter number of M’s on right side of the river: 0 Enter number of C’s on right side of the river: 0 Enter location of the boat: L The output…Consider GCET’s central library where the librarian Mario is required to sort thebooks before closing each day. The library has long shelves, and the books arenumbered through 1 to N, the librarian wishes to arrange the books so that they appearin the sequence 1,2, …, N.He intends to do this by a sequence of moves. In each move Mario can pick up anybook and insert it at a different place. Let he has 5 books and they are initially arrangedin the order: 1 4 5 3 2Mario will rearrange this in ascending order by first moving book 2 to the beginningof the shelf to get : 1 2 4 5 3Then moving book 3 to position 3, he gets 1 2 3 4 5You are required to write a program for Mario that determines the minimum numberof moves that are necessary to sort the bookshelf. C programming, please solve with full answer and solve with Flowchart and DiscriptionConsider GCET’s central library where the librarian Mario is required to sort thebooks before closing each day. The library has long shelves, and the books arenumbered through 1 to N, the librarian wishes to arrange the books so that they appearin the sequence 1,2, …, N.He intends to do this by a sequence of moves. In each move Mario can pick up anybook and insert it at a different place. Let he has 5 books and they are initially arrangedin the order: 1 4 5 3 2Mario will rearrange this in ascending order by first moving book 2 to the beginningof the shelf to get : 1 2 4 5 3Then moving book 3 to position 3, he gets 1 2 3 4 5You are required to write a program for Mario that determines the minimum numberof moves that are necessary to sort the bookshelf. please solve with Flowchart and description
- Consider the version of the dining-philosophers problem in which the chopsticks are placed at the center of the table and any four of them can be used by a philosopher. In other words, a philosopher needs four chopsticks to eat. Assume that requests for chopsticks are made one at a time. Assuming that there are m=4k chopsticks and n=6k philosophers around the table, (i) How many maximum philosophers can eat simultaneously? (ii) Describe a simple rule for determining whether a particular request can be satisfied without causing deadlock given the current allocation of chopsticks to philosophers. (Hint: Use rules similar to the Banker’s algorithm.)Correct answer will be upvoted else Multiple Downvoted. Computer science. You are given an integer n (n>1). Your assignment is to find a succession of integers a1,a2,… ,ak with the end goal that: every simulated intelligence is completely more prominent than 1; a1⋅a2⋅… ⋅ak=n (I. e. the result of this grouping is n); ai+1 is separable by simulated intelligence for every I from 1 to k−1; k is the most extreme conceivable (I. e. the length of this grouping is the greatest conceivable). In case there are a few such groupings, any of them is adequate. It tends to be demonstrated that somewhere around one substantial grouping consistently exists for any integer n>1. You need to answer t autonomous experiments. Input The primary line of the input contains one integer t (1≤t≤5000) — the number of experiments. Then, at that point, t experiments follow. The main line of the experiment contains one integer n (2≤n≤1010). It is ensured that the amount of n…We examine a problem in which we are handed a collection of coins and are tasked with forming a sum of money n out of the coins. The currency numbers are coins = c1, c2,..., ck, and each coin can be used as many times as we want. What is the bare amount of money required?If the coins are the euro coins (in euros) 1,2,5,10,20,50,100,200 and n = 520, we need at least four coins. The best option is to choose coins with sums of 200+200+100+20.
- The Josephus problem is the following game: N people, numbered 1 to N, are sitting in a circle. Starting at person 1, a hot potato is passed. After M passes, the person holding the hot potato is eliminated, the circle closes ranks, and the game continues with the person who was sitting after the eliminated person picking up the hot potato. The last remaining person wins. Thus, if M = 0 and N = 5, players are eliminated in order, and player 5 wins. If M = 1 and N = 5, the order of elimination is 2, 4, 1, 5. Write a C program to solve the Josephus problem for general values of M and N. Try to make your program as efficient as possible. Make sure you dispose of cells. What is the running time of your program? If M = 1, what is the running time of your program? How is the actual speed affected by the delete routine for large values of N (N > 100,000)? ps. provide a screenshot of output, thankssa. Given n items, where each item has a weight and a value, and a knapsack that can carry at most W You are expected to fill in the knapsack with a subset of items in order to maximize the total value without exceeding the weight limit. For instance, if n = 6 and items = {(A, 10, 40), (B, 50, 30), (C, 40, 80), (D, 20, 60), (E, 40, 10), (F, 10, 60)} where each entry is represented as (itemIdi, weighti, valuei). Use greedy algorithm to solve the fractional knapsack problem. b. Given an array of n numbers, write a java or python program to find the k largest numbers using a comparison-based algorithm. We are not interested in the relative order of the k numbers and assuming that (i) k is a small constant (e.g., k = 5) independent of n, and (ii) k is a constant fraction of n (e.g., k = n/4). Provide the Big-Oh characterization of your algorithm.In the context of evolutionary computing the goal function is known as the fitnessfunction and the problem is to maximize it. The typical formulation has to be changedin a simple way.min f (x) = − max[− f (x)] (4.9)Another requirement is that the goal function is positive.Phenotype evolution treats x as a phenotype and the goal function as the fitnessfunction. The typical framework for the method is as follows: