Q. No. 6 The current i(t) in the single loop LRC circuit when L = 0.1H, R = 20 andC = 0.1F, i(0) = 0 with impressive voltage given byS(1) = 1201 – 120tu(t – 1)is given as-1.12 - 12e-10r- 120te-10+ 12e-10(t-1) - 120te101 - 1080(t – 1)e 10(t-1) ift 21i(t) =if0 st<1-12e2.12e-10120te 10t-12e-101 + 12e-10(t-1) – 120te-104 – 1080(t – 1)e-10(-1) ift 21if0

For series RLC circuit, by KVL d2Idt2+RLdIdt+1LCI=1LE(t)put,…

Answered: Q. No. 6 The current i(t) in the single…

Q. No. 6 The current i(t) in the single loop LRC circuit when L = 0.1H, R = 20 and C = 0.1F, i(0) = () with impressive voltage given by S(1) = 1201 – 120tu(t – 1)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Norton Theorem

In the current circuit law, the Norton theorem (also known as the Mayer-Norton theorem) is a simplification that can be applied to networks generated by a constant line of opposition, power sources, and current assets. In two network terminals, it can be switched on with a current supply and single resistor respectively.

Question

Q. No. 6 The current i(t) in the single loop LRC circuit when L = 0.1H, R = 20 and
C = 0.1F, i(0) = 0 with impressive voltage given by
S(1) = 1201 – 120tu(t – 1)
is given as-
1.
12 - 12e-10r
- 120te-10
+ 12e-10(t-1) - 120te101 - 1080(t – 1)e 10(t-1) ift 21
i(t) =
if0 st<1
-12e
2.
12e-10
120te 10t
-12e-101 + 12e-10(t-1) – 120te-104 – 1080(t – 1)e-10(-1) ift 21
if0 <t<1
i(t) =
3.
12e-10t
- 120te-10
+ 120e-10(t-1) - 120te10 - 1080(t - 1)e-10(t-1) ift 21
if0 st<1
i(t) =
12e-10
4.
120te-10
-101
+ 120te 10
12e-10t
if0 st<1
- 1080(t - 1)e10(1-1) ift 21
i(t) =
-12e

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