Q1: The W12x53 tension member shown in Figure has two rows of three 1-in.-diameters in each flange. Use ASTM A992 (Fy= 50 ksi, Fu = 65 ksi). If a service dead load, PD=100 kips is applied, what is the maximum service live load, PL, that can be supported? Check all applicable yielding, rupture and block-shear failure modes. 5 O 5/½/2" O O C
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- A W12 x 79 of A572 Grade 60 steel is used as a compression member. It is 28 feet long, pinned at each end, and has additional support in the weak direction at a point 12 feet from the top. Can this member resist a service dead load of 180 kips and a service live load of 320 kips? a. Use LRFD. b. Use ASD.A W420x85 steel beam is fully restrained with a uniformly distributed live load of 25 kN/m. The beam has a span of 10m. Use A36 steel. Properties of W40 x 85 A = 10839 mm2 bf = 180 mm tf = 18 mm tw = 11 mm Ix = 310 x 106 mm4 d = 420 mm (Note: Since this is a built-up section, for checking of web slenderness, use h = d - 2tf) 1) Calculate the design shear strength of the section. Check if the section is adequate in shear. USE LRFD and U = 1.2D + 1.6L. 2) Is the maximum deflection at the midspan of the beam due to live load adequate? 3) Calculate the maximum uniform live load that can be carried by the beam.Simply Supported Beam ABCDE below carries multiple loads as shown. A built-upsection made from a T-Section and a Channel (C-Section) fastened together by 16mm∅ bolts,equally spaced from the center of the section, with shearing capacity τ=100 MPa, for bearing σb= 220 MPa for rivets in single shear and σb = 280 MPa for rivets in double shear. E=200GPa forall materials. 1.Determine the maximum flexural stress experienced by the beam in MPa.2. Determine the maximum shearing stress in MPa at Neutral Axis.3. Determine the spacing of rivets in mm.
- A bearing plate is to be designed for a W21x62, A36 steel beam that will sit on a reinforced concrete wall (fc=21 MPa) 200 mm thick. The bearing plate material has Fy = 345 MPa. The end reactions are a service dead load of 150 kN and live load of 300 kN. Determine the following using LRFD: 1. Minimum length of bearing plate to prevent web yielding, N =_________? mm. Round up by 10 mm or 25 mm. 2. Required minimum width and thickness of the bearing plate calculated assuming it is positioned at the center of the concrete wall. Use length N= 150 mm. B= _______? mm. Round up by 10 mm or 25 mm. 3. Required thickness of the bearing plate if B = 300 mm, N = 200 mm. t =________?. mm. Round up to the nearest wholeSelect the best rectangular (not square) HSS for a column to support a service dead load of 33 kips and a service live load of 82 kips. The member is 27 feet long and is pinned at the ends. It is supported in the weak direction at a point 12 feet from the top. Use Fy 5 46 ksi. a. Use LRFD. b. Use ASD.Design a column base plate for a W10 x 33 column supporting a service dead load of 20 kips and a service live load of 50 kips. The column is supported by a 12-inchx 12-inch concrete pier. Use A36 steel and f ,c= 3 ksi. a. Use LRFD. b. Use ASD
- Calculate the service load capacity in tension for an L6x4x1/2 of A36 Grade 36 steel connected with 5/8-inch dia bolts in standard holes as shown in figure 2. The angle tension member is connected to a gusset plate, typical of truss joints. The gusset plate is the plate at the intersection of members to which they are connected. Use American Institute of Steel Construction Load and Resistance Factor Design, and assume the live load to the dead load ratio is 4.0.Select a rectangular (not square) HSS for use as a 15-foot-long compression member that must resist a service dead load of 35 kips and a service live load of 80 kips. The member will be pinned at each end, with additional support in the weak direction at midheight. Use A500 Grade C steel. a. Use LRFD. b. Use ASDA plate girder must be designed for the conditions shown in Figure P10.7-4. The given loads are factored, and the uniformly distributed load includes a conservative estimate of the girder weight. Lateral support is provided at the ands and at the load points. Use LRFD for that following: a. Select the, flange and web dimensions so that intermediate stiffeners will he required. Use Fy=50 ksi and a total depth of 50 inches. Bearing stiffeners will be used at the ends and at the load points, but do not proportion them. b. Determine the locations of the intermediate stiffeners, but do not proportion them.
- Simply Supported Beam ABCDE below carries multiple loads as shown. A built-upsection made from a T-Section and a Channel (C-Section) fastened together by 16mm∅ bolts,equally spaced from the center of the section, with shearing capacity τ=100 MPa, for bearing σb= 220 MPa for rivets in single shear and σb = 280 MPa for rivets in double shear. E=200GPa forall materials. Determine the maximum flexural stress experienced by the beam in MPa.4.4-2 A W21 × 101 is used as a compression member with one end fixed and the other endfree. The length is 10 feet. What is the nominal compressive strength if Fy = 50 ksi?Note that this is a slender-element compression member, and the equations of AISCSection E7 must be used. 4.6-2 A 15-foot long column is pinned at the bottom and fixed against rotation but free totranslate at the top. It must support a service dead load of 100 kips and a service liveload of 100 kips.a. Select a W12 of A992 steel. Use the column load tables.1. Use LRFD.2. Use ASD.b. Select a W16 of A992 steel. Use the trial-and-error approach covered in Section 4.6.1. Use LRFD.2. Use ASD.A welded tension member is consisting of two channels placed 400mm back to back with flanges turned out. Select a channel for factored tensile of 4RKN using A36 steel and AISC specifications.The member is to be 15m long. Take R= 433.5 Factored design load= R*4