Solve question 1 R-8,314 1/K.mol F-96485 N, 6.022x101 2 345 6 78 9 10 11 12 13 14 15 16 17Q1. The conductivity of 0.02 M KCl solution at 25 °C is 2.768x10 S.cm Theresistance of this solution at 25 C when measured with a particular cell was 250.2 02. Theresistance of 0.01 NaCl at 25 C with the same cell was 200.0 2. Calculate the molarconductivity (Sem'mol) of the NaCl solution.A) 124.8B) 346 3C) 279 9D) 456,3E) 232.4In order to find K., value for a weak acid (AB), three strong electrolytes (AC, NBand NC) were chosen. The graph aside is for AC electrolyteQ2 The molar conductivity of strong electrolyte atAC Strong Electrolyteinfinite dilution (A) equals.A) The slope of Am versus concentration graph accordingto Onsager equation.B) The slope of A versus the square root of concentrationgraph according to Oswald's law.C) The intercept of Am versus the square root of concentrationgraph according to Onsager equation.D) The intercept of A versus concentration graph accordingto Oswald's law.1818340.41214300.0BLOME41030.0066.00الأسمv-405.95x 183.31-0.9473das8.108.15x-variableQ3. The molar conductivity (Sem'mol") at infinite dilution for AC isA) 183.3B) 406.5C) 138.2D) 380.1Q4. If A-170 for NB, and A" 165.2 for NC, the molar conductivity at infinitedilutiofor AB isA) 178.36.10B) 188.11 C) 150.87 D) 142.99Based on the following plot that was obtained from the experiment of determiningthe dissociation constant of weak organic acid using conductivity measuremenQ5. Both molar conductivity at infinite dilution (A) and dissociation constant (K₂)for the acid can be determined by plotting..VS.....A) 1/A vs. CAmB) Am vs. Vc. C) Am Vs. C D) CA, VS. VEQ6. The molar conductivity at infinite dilution (A) for the acid equalsA) 213B). 333C) 786D) 456Q7. Calculate the equilibrium constant at 25 "C for the reaction2Fe (aq) +2 (aq)-2 2Fe²(aq) + 1:(s)Given the standard reduction potentials:2Fe +2e2Fe²+ E-0.771 V1₂ +2e21A) 18.31E-0.5355 VB) 9.3C) 9.10x10 D) 9.54x10' E) 2.9x10Q8. In the reaction of hydrolysis of ethyl acetate in acid medium, the rate constant at40°C is 12,6 s and at 80°C is 46.5 s. The activation energy (E) in kJ/mol is:C) 25.0D) 29987A) 25780B) 30.009. In the iodination of acetone experiment, the reaction rate is followed through titrationof 12 with 0.1 M SO.. If volume of 1₂ used for titration is 10 ml. A plot of V vst isconstructed with the equation of line: Y-2.8 X. Determine the rate constant KD) 2.42E) 0.642A) 0.853C) 0.014B) 1.610.30Yes.com835

Answered: Image /qna-images/answer/370f7d09-3ef9-4f87-9054-185c5d393a1e.jpg

Q1. The conductivity of 0.02 M KCI solution at 25 °C is 2.768x10 S.cm The resistance of this solution at 25 C when measured with a particular cell was 250.2 02. The resistance of 0.01 NaCl at 25 C with the same cell was 200.0 12. Calculate the molar E) 232.4 conductivity (Scm'mol) of the NaCl solution. A) 124.8 B) 346 3 C) 279.9 D) 456.3 NR

Q1. The conductivity of 0.02 M KCI solution at 25 °C is 2.768x10 S.cm The resistance of this solution at 25 C when measured with a particular cell was 250.2 02. The resistance of 0.01 NaCl at 25 C with the same cell was 200.0 12. Calculate the molar E) 232.4 conductivity (Scm'mol) of the NaCl solution. A) 124.8 B) 346 3 C) 279.9 D) 456.3 NR

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter11: Properties Of Solutions

Section: Chapter Questions

Problem 109AE: Patients undergoing an upper gastrointestinal tract laboratory test are typically given an X-ray...

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Patients undergoing an upper gastrointestinal tract laboratory test are typically given an X-ray contrast agent that aids with the radiologic imaging of the anatomy. One such contrast agent is sodium diatrizoate, a nonvolatile water-soluble compound. A 0.378-m solution is prepared by dissolving 38.4 g sodium diatrizoate (NaDTZ) in.l.60 102 mL water at 3 1.2C (the density of water at 31.2C is 0.995 g/cm3). What is the molar mass of sodium diatrizoate? What is the vapor pressure of this solution if the vapor pressure of pure water at 31.2C is 34.1 torr?
A conductivity cell has a resistance of 250 Ω when filled with 0.02 M KCl at 25°C and 105 Ω when filled with 6 x 10-5 M ammonium hydroxide solution. The conductivity of 0.02 M KCl solution at 25°C is 0.277 Sm-1, and the limiting molar ionic conductivities of NH4 + and OH- are 7.34 x 10-3 and 0.0198 S m2mol-1 , respectively. Calculate the cell constant and degree of dissociation of ammonium hydroxide in the 6 x 10-5 M solution.
4.In a certain conductivity cell, the resistance of a 0.01 M KCl solution is 150 Ω. Theknown molar conductivity of the solution is 141.27 Ω-1 cm2 mol-1. Calculate the cell constant (Kcell).*(Kcell unit is cm-1) 5. Using the same conductance cell as in Question No. 4, a student measured the resistanceof a 0.10 M NaCl solution to be 19.9Ω. Calculate the experimental value of the molarconductivity of this solution.
1. Give the molar concentration of HCl with a specific gravity of 1.18 and 37.0% (w/w) purity (MM=36.5g/mol) 2. A solution made by adding 1.63 g of K2S (MM=110.3 g/mol) to 10.0 mL of H2O has a volume at 20oC of 11.1 mL. Find the molarity and normality of the solution.
Why is the conductivity of mixture C larger than the conductivity of mixture A? C Mixture made by mixing equal volumes of 0.2 mol L–1 HCl and 0.2 mol L–1 NaCl Conductivity (mA) 340 PH 1 A 0.1 mol L–1 HCl 260 1
) 0.025 M CH3COOH solution has a specific conductance of 2.33X10-4 Scm-1,and molar conductivity at infinite dilution is 364.13 S.Cm2.mol-1. What is itsdegree of dissociation?
The molar conductivities at infinite dilution of aqueous solutions of NH4Cl, NaCl, and NaOH are, respectively, 130, 108.6, and 216.5 S cm2 mol-1 at 18°C. The specific conductivity of a 0.01 M solution of ammonia at the same temperature is 9.6 x 10-5 [S cm-1] and the ion product of water is 0.59 x 1014. Determine: • The concentration of NH4+ ions in the ammonia solution. • The pH of the ammonia solution.
1. What is the MW of the analyte?2. What is the meq of the analyte?3. What will be the weight (in grams) of the analyte if the standardization is to be quartered?4. What will be Normality of the solution if 7.5ml of the titrant was consumed in the standardization?5. What is the average Normality if two or more trials were conducted with the values of 0.102N and 0.105N?
Calculate the osmolarity in mOsm/L of 500 mL of a solution containing 5% w/v dextrose, 0.78% w/v sodium chloride, and 27mEq of potassium acetate. dextrose: MW 180, # particles on dissociation 1 sodium chloride: MW 58.5, # particles on dissociation 2, valence 1 potassium acetate: MW 98, # particles on dissociation 2, valence 1
5 mL of HCl and 5 mL of CH3COOH solutions are titrated with a pipette in a glass bottle and 150 mL of distilled water is added. The initial conductivity (720) of this diluted mixture is measured and recorded in the table. Then, one ml of M/10 NaOH solution is added and their conductivity is measured and recorded in the table. Find the concentration of HCl and CH3COOH.
The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm-1. Calculate its molar conductivity.
The resistance of a conductivity cell containing a 0.02 M aqueous solution of KCl was fond to be 83 ohms at 298 K. The conductivity of the 0.02 M KCl solution at this temperature is 0.00277 S cm-1. When the cell was filled with a 0.005 M aqueous solution of K2SO4, it exhibited a resistance of 326 ohms at the same temperature. What is the molar conductivity of the potassium sulfate solution? [ answer should be 141 S cm2 mol-1]thank u