Q15) Given that y₁ (t) = t¹ is solution for 2t2y" + ty' - 3y = 0,t> 0, then y₂ (t) is: a) t b) tz e-at sin3t atsinst Q16) L-¹ (5-3)²+25) d) = a) estsinst 5 est sin3t 5 b) 5 5 18

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