Q2- Design the hardware required to interface 128KB of SRAM to the demultiplexed address and data bus of the 8086 Microprocessor connected in minimum mode using 64Kx8 memory chips. Decode the memory with simple NAND gate decoder so that it starts from physical address 00000h also for each memory chip used in your Design determines the physical address which can handle.
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- If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?MIPS ISA has registers of 32-bits which are employed to create a 64-bit base address which is especially used for instructions like Load Word and Store Word. May these Load Word and Store Word instruction formats contain a random pair of source registers to create the base address? If yes, explain if there will be any corresponding effects and what they will be? If no, why not?The 8051 serial port supports full duplex operation, with transmit and receive buffersthat are available via the SBUF register. Each buffer has an interrupt flag, symbolisedas TI and RI, respectively.i) Briefly state what is meant by full duplex communication. ii) Write a small assembly language program to show how the serial interface can beused for the reception of characters using the serial interface interrupt. Thereceived character(s) should be copied into R0. You must show how theinterrupt is configured; however, you can omit all details of the timer setup. iii) Assuming this code is run on a classic 8051 using a 16 MHz crystal, show howyou would configure Timer 1 for a baud rate 9600 bits/sec and calculate theresulting percentage error. Assume the serial interface is set for 8-bit UART mode,the SCON bit is 0, and the timer is to operate in 8-bit auto-reload mode. You mustshow the values of SCON, TCON, TMOD and TH1.
- We want to build a byte organized main memory of 8 GB for a 32-bit CPU architecture composed ofbyte organized memory modules of 30-bit address and 8-bit data buses each.a) Draw the interface of the main memory by clearly indicating the widths of the buses.b) How many memory modules would be necessary to build the memory system?c) Design the main memory internal organization built out of the above memory modules (usemultiplexers and/or decoders as needed) by clearly indicating the widths of the used bussesd) Can we use this memory system as RAM for the CPU in Problem 1? Explain your answer.Interface 256KB EEPROM with 8088 microprocessor. Memory map for total EEPROM is 40000H and above. Your design must use NAND decoder. You are required to provide: A. Completely labelled schematic diagram to interface EEPROM with 8088 microprocessor. B. Starting and ending memory address of the memory chip. kindly provide its solution in handwritten form Regards MHRWhat is the purpose of address decoding and explain the difference between full andpartial address decoding. Assuming the address bus is 16-bit wide, using the addresslines with no additional logical gates, how many 1024-Byte memory devices could besupported if each has a single Chip-Enable pin? Explain your answer.
- Question 12 kana.In MIPS architecture. What is the memory hierarchy? Why does it work? What are two important mechanisms that address the Speed problem and the Size problem? Full explain this question and text typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this lineThe Intel80486 has on-chip, unified cache. It contains 8Kbytes and has a four way set associative organization and a block length of four 32-bit words. The cache is organized into 128 sets. There is a single “line valid bit” and three bits,B0,B1,B2 (the LRU bits) per line. On a cache miss, the 80486 reads a 16 byte line from main memory in a bus memory read burst. Show the details for the different fields of the address.in 80886 microprocessor Suppose that. DS = 0200H, BX = 0300H, and DI-400H Determine the memory address accessed by each of the following instructions, assuming real mode operation: (1) MOV AL,[1234H] (2) MOV AX,[BX] (3) MOV [DI]AL
- 2. This question is about Digital Logic and Address DecodingA computer is being designed using a microprocessor with a 16-bit address bus (A0—A15, where A0 is the least significant bit). The 64K address space is to be split betweenand allocated to RAM, ROM and I/O hardware as follows:Address Range (hex) Contains Select Signal0x0000 — 0x1FFF Main RAM RAMCS0x8000 — 0x9FFF Video RAM VRAMCS0xB000 — 0xBFFF I/O hardware IOCS0xC000 — 0xCFFF BASIC ROM BROMCS0xF000 — 0xFFFF OS ROM OSROMCSThe rest of the address space is unused.Note: As with many computer systems, it its only necessary to decode addresses to sufficiently identify each of the sections above uniquely. It is acceptable for some parts to be decodeable by more than one address provided these extra addresses do not overlap any of the other specified address ranges. Using a combination of AND, OR and NOT gates and the signals (A12 — A15) that contain the top four bits of the address in binary form: a. Derive the equation for a logic…How can I compute sum of each of the component latencies for each instruction? Question 1: This is a three-part question about critical path calculation. Consider a simple single-cycle implementation of LEGv8 ISA. The operation times for the major functional components for this machine are as follows: Component Latency ALU 90 ps Add 70 ps ALU Control Unit 30 ps Shifter 20 ps Control Unit/ROM 50 ps Sign/zero extender 20 ps 2-1 MUX 20 ps Memory (read/write) (instruction or data) 140 ps PC Register (read action) 20 ps PC Register (write action) 20 ps Register file (read action) 80 ps Register file (write action) 60 ps Logic (1 or more levels of gates) 10 ps Below is a copy of the LEGv8 single-cycle data path design. In this implementation the clock cycle is determined by the longest possible path in the machine. The critical paths for the different instruction types that need to be considered are:…The register content for an Intel 8086 microprocessor is as follows:CS = 1000H, DS = 2000H, SS = 5000H, SI = 2000H, DI = 4000HBX = 6783H, BP = 7000H, AX = 29FFH, CX = 8793H, DX = A297HCalculate the physical address of the memory where the operand is stored and the contents of the memory locations in each of the addresses shown below: a) MOV [SI], ALb) MOV [DI+6H], BXc) MOV [SI+BX–11], AXd) MOV [DI][BX]+28H, CXe) MOV [BP][SI]+17, DX