Q2/ The following data stream (10011011 11001110 11110000 10001000 11100000 11011010 11111111 0111011i 10011001 11100111 01011010) will be transmitted with signaling rate equal to 80 k bit/sec. - Find the Hamming code of the last byte of the data only in which two error can be detected and one error can be corrected, calculate the transmitted bandwidth? how can reduce the transmitted bandwidth? Explain and calculate the reduced transmitted bandwidth? By using the following polynomial calculate the data transmitted of the (first byte of the data only) (p= x5 +x3 +x+l).

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Q2/ The following data stream (10011011 11001110
11110000 10001000
11100000
11011010 11111111 01110111 10011001 11100111
01011010) will be transmitted with signaling rate equal to 80 k bit/sec.
2- Find the Hamming code of the last byte of the data only in which two error
can be detected and one error can be corrected, calculate the transmitted
bandwidth? how can reduce the transmitted bandwidth? Explain and calculate
the reduced transmitted bandwidth?
3- By using the following polynomial calculate the data transmitted of the (first
byte of the data only) (p= x5 +x3 +x+l).
Transcribed Image Text:Q2/ The following data stream (10011011 11001110 11110000 10001000 11100000 11011010 11111111 01110111 10011001 11100111 01011010) will be transmitted with signaling rate equal to 80 k bit/sec. 2- Find the Hamming code of the last byte of the data only in which two error can be detected and one error can be corrected, calculate the transmitted bandwidth? how can reduce the transmitted bandwidth? Explain and calculate the reduced transmitted bandwidth? 3- By using the following polynomial calculate the data transmitted of the (first byte of the data only) (p= x5 +x3 +x+l).
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