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- This assignment is a step-by-step assignment where you build on the previous step so Please added to the existing code that I have #include <stdio.h> int printBin(int value); int main(){ int num=10; int tobinary= printBin(num); printf("The number %d converted to binary as %d \n ",num,tobinary); unsigned int x = 1; char *ccc = (char*)&x; if(*ccc){ printf("This is Little endian"); } else{ printf("This is Big endian"); } getchar(); return 0; } int printBin(int value) { if(value<2) return value; return printBin(value / 2) *10 + value % 2; }PROGRAM C int getNum(); /*accepts input from the user.*/ long decBin(int n); /* returns the binary equivalent of n. Note: Use of built in functions that will automatically convert decimal to binary is not allowed. */ void display(long binary); /*displays the binary equivalent*/ ------------------------------------------------------------------------Examine the following code segment. What will be printed? If there are any errors indicate the nature of the error. int a[9] = { 1, 12, 3, 14, 25, 16, 7, 8, 9 }; int *ptr ; ptr = & a[ 2 ] ; for( i = 1; i <= 5; i = i + 2) cout << a[i] << *( ptr + i ); cout << ” ” << a[0] << ” ” << *ptr << ” ” << *ptr - 1 << ” ” << *(ptr - 2));
- Manually trace the following code to analyze how it works #include <iostream> using namespace std; int main() { int n = 5; for (int row = 0; row < n; row++) { for (int col = 0; col < n; col++) { cout << "*"; } cout << endl; } } Based on the above s SquareCode, generate a code fragment “firstTriangle” in your main() that reads in an integer n and displays the following triangle assuming n=5. The only couts you may use are cout <<“*” and cout << endl; Hint: write out a table showing for each row, how may columns you will need to display.***************What will be the value of ans after the following code has been executed? int x = 90, y = 55, ans = 10; if ( x == y); ans *= 2; 1. 10 2. 145 3. 20 4. None of theseFirst, write code that uses cin to read in a value for numPears from input. Then, write code that uses cout to output "The store has ", the variable numPears, and " pears." End with a newline. Ex: If the input is 5, then the output is: The store has 5 pears. Ex: If the input is 7, then the output is: The store has 7 pears. #include <iostream>using namespace std; int main() { int numPears; /* Your code goes here */ return 0;}
- - can you modify my answer, so that i can get a 6% discount if 'AE6GY' promo code is entered #include <iostream> using namespace std;void menu(){ cout << "******Welcome to the Farhan's Restaurant******" << endl; cout<<"_________________________________________________"<<endl; cout<<"No. Menu Price"<<endl; cout<<"1. Cheese Burger RM 8"<<endl; cout<<"2. Chicken Wings(6 pieces) RM 10"<<endl; cout<<"3. 12\" Pepperoni Pizza RM 20"<<endl; cout<<"4. Fries RM 5"<<endl; cout<<"5. Onion Rings RM 6"<<endl; cout<<"6. Pepsi RM 2"<<endl; cout<<"7. Mineral Water RM 3"<<endl; } main(){ string phone; //we use string so that the 0 value can be displayed string Name; cout<<"Please enter your name :";…int fun(int k){ return ( ); void main(){ int n; cin >> n; n = n * fun(n); <-- 1 Fill in the appropriate statement and expression in fun, so that when it is called in main, and after the execution of the statement marked 1, the value of n would always be n3.3. B) What is the value of num when the following code snippet runs successfully? int num = 100; if (num < 100) { if (num < 50) { num -= 5; } else { num -= 10; } } else { if (num > 150) { num += 5; } else { num += 10; } } C) A store provides 10 percent discount on all items with a price of at least $100. No discount is otherwise applicable. Assume that two variables are declared, discount and price. Write the code segment that does the job.
- What does the following code segment display? for(f=0; f<3; ++f); write ("{0} ", f); a. 0 b. nothing c. 3 d. 0 1 2The following statement is incorrect. Write the correct statement. a = (x < 16) : 5 ? 11Why won't this code run in C++? #include<iostream>#include<stdlib>void main(){int A,B,i,sum=0;cout<<endl<<"Enter any two even numbers: ";cin>>A>>B;if(A%2==1||B%2==1) // checking whether given numbers are even or not{cout<<"Invalid input: Enter only even numbers"<<endl;exit(1);}else if(A>B) // checking whether A is greater than B or not{cout<<"Invalid input: First number A must be smaller than Second number B"<<endl;exit(1);}else{for(i=A;i<=B;i++){if(i%2==0) // checking for even number{sum=sum+(i*i);}}}cout<<"Sum of even numbers between "<<A<<" and "<<B<<" is "<<sum<<endl;}