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Q3// For the reaction bellow: C„H 2n+2) + a(02 + 3.76 N2) → nC02 + (n + 1)H,0 + 3.76a N2 If the heat of combustion writing as: Qe = 618.49 n + 187.83 (KJ/mole of fuel) And the mole fraction of CO, in products is Xco, 1. Type of fuel. find: 2. Heat of combustion 3. If n=4, find the mole fractions of CO, H;0 and N2

Q3// For the reaction bellow: C„H 2n+2) + a(02 + 3.76 N2) → nC02 + (n + 1)H,0 + 3.76a N2 If the heat of combustion writing as: Qe = 618.49 n + 187.83 (KJ/mole of fuel) And the mole fraction of CO, in products is Xco, 1. Type of fuel. find: 2. Heat of combustion 3. If n=4, find the mole fractions of CO, H;0 and N2

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Q3// For the reaction bellow: C,H 2n+2) + a(0, + 3.76 N2) - nC0, + (n + 1)H20 + 3.76a N2 If the heat of combustion writing as: Q. = 618.49 n + 187. 83 And the mole fraction of CO, in products is Xco, 1. Type of fuel. (KJ/mole of fuel) , find: 25 227 2. Heat of combustion 3. If n=4, find the mole fractions of Co, H,0 and N2
Transcribed Image Text:Q3// For the reaction bellow: C,H 2n+2) + a(0, + 3.76 N2) - nC0, + (n + 1)H20 + 3.76a N2 If the heat of combustion writing as: Q. = 618.49 n + 187. 83 And the mole fraction of CO, in products is Xco, 1. Type of fuel. (KJ/mole of fuel) , find: 25 227 2. Heat of combustion 3. If n=4, find the mole fractions of Co, H,0 and N2
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