Q3. A single-phase 240/2400, 50 Hz, transformer has the equivalent circuit parameters referred to high voltage side Rc =6 2, Xm =3 2, Req2 -25 S2, Xeq2 =75 2. The transformer is supplying a load of 400+ j200 2. Keeping the primary voltage of 240 V, calculate the following: (a) secondary terminal voltage referred to low voltage side (b) current in the primary winding

Q3. A single-phase 240/2400, 50 Hz, transformer has the equivalent circuit parameters referred to high voltage side Rc =6 2, Xm =3 2, Req2 -25 S2, Xeq2 =75 2. The transformer is supplying a load of 400+ j200 2. Keeping the primary voltage of 240 V, calculate the following: (a) secondary terminal voltage referred to low voltage side (b) current in the primary winding

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter3: Power Transformers

Section: Chapter Questions

Problem 3.57P: A two-winding single-phase transformer rated 60kVA,240/1200V,60Hz, has an efficiency of 0.96 when...

See similar textbooks

Similar questions

A two-winding single-phase transformer rated 60kVA,240/1200V,60Hz, has an efficiency of 0.96 when operated at rated load, 0.8 power factor lagging. This transformer is to be utilized as a 1440/1200-V step-down autotransformer in a power distribution system. (a) Find the permissible kVA rating of the autotransformer if the winding currents and voltages are not to exceed the ratings as a two-winding transformer. Assume an ideal transformer. (b) Determine the efficiency of the autotransformer with the kVA loading of part (a) and 0.8 power factor leading.
Q3- A 10 KVA, 230/ 110 V transformer is to be used as an auto-transformer. What will be the voltage ratio and output power rating of auto-transformer Q4-A single-phase, 10-kVA, 440/110-V, two- winding transformer is connected as an autotransformer to supply a load at 550 V from a 440 V supply as shown below. Calculate the following. 1. kVA rating as an autotransformer 2. apparent power transferred by conduction 3. apparent power transferred by electromagnetic induction
A 20-kVA, 440/220 V, 1-phase, 50 Hz transformer has iron loss of 324 W. The Cu loss is found to be 100 W when delivering half full-load current. Determine (i) efficiency when delivering full-load current at 0.8 lagging p.f. and (ii) the percent of full-load when the efficiency will be maximum.
Mechanical Engineering Course, Electrical subject questions! (refer attached pic) A 20kVA 8000/277V distribution transformer has the following resistances and reactances:Re, = 32 ohmRs0.050 ohmXp45 ohmXs0.060 ohmR. = 250k ohmXM30k ohmThe excitation branch impedances aregiven referred to the high-voltageside of thetransformer. Assume that this transformer is supplying rated load at 277 V and 0.85 pflagging, determine the following:=:Draw and label the equivalent circuit of transformer referred to primary sidein)Determine its voltage regulation and efficiency.
The rating of a current transformer is expressed as 20VA/10/15. Assume that the secondary resistance of the CT is 0.15 ohm, calculate the new accuracy limit factor when the burden becomes one quarter (1/4). The current rating is 5 A.
Q2: A 4000/400 V, 10 kVA transformer has the following constants:Primary and secondary winding resistances of 13 Ω and 0.15 Ω respectivelyLeakage reactance referred to primary is 45 ΩResistance of equivalent exciting circuit referred to primary, R0 = 12k ΩReactance of equivalent exciting circuit referred to primary, X0 = 6k ΩWhat would be the reading of the instruments when the transformer is connected for theopen-circuit and short-circuit tests? Compute the voltage regulation for full load at 0.8 p.f.lagging.
A 1-phase, 10-KVA, 500/250-V, 50-Hz transformer has the following constants: Reactance: primary 0.2 ohms; secondary 0.5 ohms Resistance: primary 0.4 ohms; secondary 0.1 ohms Resistance of equivalent exciting circuit referred to primary, Rm = 15000 Reactance of equivalent exciting circuit referred to primary, Xc = 750 Ohms What would be the reading of the ammeter connected in the low voltage secondary when the transformer is connected fopen-circuit tests?
A 1-phase, 10-KVA, 500/250-V, 50-Hz transformer has the following constants: Reactance: primary 0.2 0; secondary 0.5 Q Resistance: primary 0.4 0; secondary 0.10 Resistance of equivalent exciting circuit referred to primary, Rm = 1500 Q Reactance of equivalent exciting circuit referred to primary, Xc = 750 0 What would be the reading of the ammeter connected in the low voltage secondary when the transformer is connected for short-circuit tests?
A single-phase 1,000 VA, 230/115 V transformer has been tested to determine its equivalent circuit. The results of the tests are shown in Table. 1. All the data given in the Table. 1 were taken from the primary (high voltage) side of the transformer. a) Find the equivalent circuit of this transformer referred to the low-voltage side of the transformer b) Neglecting magnetizing impedance, find the transformer’s voltage regulation at rated conditions andi) 0.8 power factor laggingii) 1.0 power factoriii) 0.8 power factor leading c) Including magnetizing impedance, determine the transformer’s efficiency at rated conditionsand 0.8 power factor lagging. Table 1. Open-circuit test Short-circuit test VOC = 230 V IOC = 0:45 A POC = 30 W VSC = 19:1 VISC = 8:7 APSC = 42:3 W
A single-phase distribution transformer has a specified 13.8 KV/ 480 V. When the transformer is excited at nominal voltage on the high voltage side, with the low voltage winding in open circuit, it takes 0.35 A and 1610 W. When the winding low voltage terminal is shorted, and 1000 V is applied to the high voltage terminals, the readings are 66 A and 382 W. Find: a) The values corresponding to the equivalent circuit of the transformer referred to the low voltage side.
A commercial 60-Hz, 440/110-volt, 50-kVA power transformer has 600 turns on its high-voltage side. Calculate: (a) number of turns on its low-voltage (L.V.) side. (b) a, when used as a step-down transformer and as a step-up transformer (c) volts/turn ratio of low-voltage (L.V.) side
A transformer with 10: 1 rato and rated at 50 KVA, 2400 7 240 V, 50 Hr is used to step down the voltage of a distrbution system. The low-tension voltage is to be kept constant at 240 V i. What load impedance connected to the low-tension side will be loading the transformer fully at 0.8 power factor lagging? ii.What is the value of this impedance referred to high-tension side? iii. What is the value of this impedance referred to high-tension side?